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3 years ago

Plz answer. I need the information now

Mathematics

2 answers:

Alina [70]3 years ago

8 0

Answer:

Angles 10 and 11

Step-by-step explanation:

For angles to be supplementary, they must add up to 180 degrees and be next to each other. By looking at the figure, we can see the only pair of angles that fit these criteria are angles 10 and 11.

Maksim231197 [3]3 years ago

6 0

Step-by-step explanation:

it is angle 10 and angle 11 this is because supplementary angles add up to 180°

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Maru [420]

Answer:

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4 years ago

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Find the missing value. Show your work. Round to the nearest hundredth

Alexxandr [17]

Well the angle for C is 90 degrees.

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3 years ago

if 10 800 cm2 of material is available to make a box with a square base and an open top find the largest possible volume of the

lubasha [3.4K]

Let

x--------> the length side of the square base of the box

y-------> the height of the box

we know that

The surface area of the box is equal to

$SA=4xy+x^{2}$

$SA=10,800\ cm^{2}$

$10,800=4xy+x^{2}$

$y=(10,800-x^{2})/(4x)$

$y=(2,700-0.25x^{2})/(x)$ --------> equation A

the volume of the box is equal to

$V=x^{2}y$ --------> equation B

Substitute the equation A in the equation B

$V=x^{2}*(2,700-0.25x^{2})/(x)$

$V=x*(2,700-0.25x^{2})$

$V=(2,700x-0.25x^{3})$

using a graphing tool

see the attached figure

For $x=60\ cm$

$Volume=108,000\ cm^{3}$

the point $(60,108,000)$ is a maximum of the function

Find the dimensions of the box

$x=60\ cm$

Find the value of y

$V=x^{2}y$

$y=V/x^{2}$

$y=108,000/60^{2}$

$y=30\ cm$

The dimensions of the box are

$60\ cm*60\ cm*30\ cm$

The largest possible volume of the box is

$108,000\ cm^{3}$

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3 years ago

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3 years ago

Which equation is in standard form?

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keeping in mind that

standard form for a linear equation means

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• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

3x + 4y = 10.

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3 years ago