16/4, 40/10,100/25. those are all improper fractions that equal 4. hope that helps
Answer:
A) The value of a is <u>29</u>.
B) The value of b is <u>greater than 29</u>.
C) In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.
D) The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.
Step-by-step explanation:
Solving for Part A.
Given,

We have to solve for a.

By using addition property of equality, we will add both side by 9;

Hence the value of a is <u>29</u>.
Solving for Part B.
Given,

We have to solve for b.

By using addition property of inequality, we will add both side by 9;

Hence the value of b is <u>greater than 29</u>.
Solving for Part C.
In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.
Solving for Part D.
The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.
Answer:
We cannot say it's different Difference ot of Two Cubes because 2d2 is not not cube it's square. and 8d is not a cube.
We cannot say Difference of Two Squares because only first term 2d2 has a square.
It is not a Perfect Square Trinomials because Perfect Square Trinomials appears as ax2 + bx + c, but the given ter doesn't follow this.
A. Common Monomial Factor can be regarded as a variable, or more than one variable that that is present in the polynomial terms.
Example is 4x2 + 16x,
If factorize we have 4x(x + 4) with monomer of 4x and polynomial of x + 4). that cannot be factorized into lower polynomial.
Hence 2d2-8d can be factor as 2d(d-4) where 2d is the monomer and (d-4) cannot be factorize into lower degree polynomial.
Answer:
the answer is definitely d
Answer:$29.64
Step-by-step explanation:
$22.80 + 30%= $29.64