To find missing lengths of sides
hope this helped have a nice day
Answer:
69
Step-by-step explanation:
The sum of exterior angles is 360°, so ...
n° +131° +160° = 360°
n° = 360° -291° = 69°
n = 69
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Answer:
i can explai it to u if u wan to get the answer
Step-by-step explanation:
Divide the polygon into 5 triangles by using each side as a base and joining the vertices of the polygon to a common point (for example, the centre). If the polygon is regular the angle at the vertex of each triangle is 360/5=72 degrees, so you have 5 isosceles triangles of equal area. Find the area of one and multiply by 5 to get the total area.multiply 5 times the lenght of oneside
Check the picture below.
since we know that x = 3/7, we can then plug that on either of the twin legs, since it's an isosceles, and get the length of each leg, so say let's plug it in 5x + 16
![5x + 16\implies 5\left( \cfrac{3}{7} \right)+16\implies \cfrac{38}{7}+16\implies \cfrac{38+112}{7}\implies \cfrac{150}{7}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\\stackrel{\textit{both legs}}{\cfrac{150}{7}+\cfrac{150}{7}}+\stackrel{\textit{base}}{6}\implies \cfrac{150+150+42}{7}\implies \cfrac{342}{7}\implies 48\frac{6}{7}\impliedby \textit{perimeter}](https://tex.z-dn.net/?f=5x%20%2B%2016%5Cimplies%205%5Cleft%28%20%5Ccfrac%7B3%7D%7B7%7D%20%5Cright%29%2B16%5Cimplies%20%5Ccfrac%7B38%7D%7B7%7D%2B16%5Cimplies%20%5Ccfrac%7B38%2B112%7D%7B7%7D%5Cimplies%20%5Ccfrac%7B150%7D%7B7%7D%5C%5C%5C%5C%5B-0.35em%5D%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%5Cstackrel%7B%5Ctextit%7Bboth%20legs%7D%7D%7B%5Ccfrac%7B150%7D%7B7%7D%2B%5Ccfrac%7B150%7D%7B7%7D%7D%2B%5Cstackrel%7B%5Ctextit%7Bbase%7D%7D%7B6%7D%5Cimplies%20%5Ccfrac%7B150%2B150%2B42%7D%7B7%7D%5Cimplies%20%5Ccfrac%7B342%7D%7B7%7D%5Cimplies%2048%5Cfrac%7B6%7D%7B7%7D%5Cimpliedby%20%5Ctextit%7Bperimeter%7D)
