All categories

3 years ago

2x + y = -8 3x - 5y = -25

Mathematics

1 answer:

Margarita [4]3 years ago

6 0

Answer:

x=-5, y=2. (-5, 2).

Step-by-step explanation:

2x+y=-8

3x-5y=-25

------------------

5(2x+y)=5(-8)

3x-5y=-25

-------------------

10x+5y=-40

3x-5y=-25

--------------------

13x=-65

x=-65/13

x=-5

2(-5)+y=-8

-10+y=-8

y=-8-(-10)=-8+10=2

You might be interested in

38F hotter or 2C (Tempture)

viva [34]

38* F is hotter. 2*C is only 35.6*

4 0

3 years ago

Read 2 more answers

Vaselesa [24]

The mass of the object is 13 kg.

4 0

3 years ago

Use f’( x ) = lim With h ---> 0 [f( x + h ) - f ( x )]/h to find the derivative at x for the given function. 5-x²

beks73 [17]

<h2>Answer:</h2>

The derivative of the function f(x) is:

$f'(x)=-2x$

<h2>Step-by-step explanation:</h2>

We are given a function f(x) as:

$f(x)=5-x^2$

We have:

$f(x+h)=5-(x+h)^2\\\\i.e.\\\\f(x+h)=5-(x^2+h^2+2xh)$

( Since,

$(a+b)^2=a^2+b^2+2ab$ )

Hence, we get:

$f(x+h)=5-x^2-h^2-2xh$

Also, by using the definition of f'(x) i.e.

$f'(x)= \lim_{h \to 0} \dfrac{f(x+h)-f(x)}{h}$

Hence, on putting the value in the formula:

$f'(x)= \lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-(5-x^2)}{h}\\\\\\f'(x)=\lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-5+x^2}{h}\\\\i.e.\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2-2xh}{h}\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2}{h}+\dfrac{-2xh}{h}\\\\f'(x)=\lim_{h \to 0} -h-2x\\\\i.e.\ on\ putting\ the\ limit\ we\ obtain:\\\\f'(x)=-2x$