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3 years ago

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How can we use 1/2 inch edge lengths to find the volume of a prism that is 1/2 inch by 2 inch by 3 1/2 inches? I will mark brain

liest!

1 answer:

lora16 [44]3 years ago

6 0

Volume is length times width times height so multiply those

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IF YOU GET ANSWR RIGHT YOU GET BRAINLIEST!

ollegr [7]

Answer:

b

Step-by-step explanation:

4 0

3 years ago

Consider the following hypothesis test.H0:μ1−μ2=0 Ha:μ1−μ2≠0The following results are for two independent samples taken from the

Julli [10]

Answer:

a) $z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

b) $p_v =2*P(z$

c) Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

Step-by-step explanation:

Information given

$\bar X_{1}= 104$ represent the mean for 1

$\bar X_{2}= 106$ represent the mean for 2

$\sigma_{1}= 8.4$ represent the population standard deviation for 1

$\sigma_{2}= 7.6$ represent the population standard deviation for 2

$n_{1}=80$ sample size for the group 1

$n_{2}=70$ sample size for the group 2

z would represent the statistic

Hypothesis to test

We want to check if the two means for this case are equal or not, the system of hypothesis would be:

H0: $\mu_{1}=\mu_{2}$

H1: $\mu_{1} \neq \mu_{2}$

The statistic would be given by:

$z =\frac{\bar X_1-\bar X_2}{\sqrt{\frac{\sigma^2_1^2}{n_1} +\frac{\sigma^2_2^2}{n_2}}}=$ (1)

Part a

Replacing we got:

$z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

Part b

The p value would be given by this probability:

$p_v =2*P(z$

Part c

Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

6 0

3 years ago

Find (fºg)(1)<br> f(x) = x² - 1<br> g(x) = √x <br> A.0<br> B.1<br> C.4 √2<br> D. √8

Savatey [412]

Given:

The function are

$f(x)=x^2-1$

$g(x)=\sqrt{x}$

To find:

The value of $(f\circ g)(1)$ .

Solution:

We have,

$f(x)=x^2-1$

$g(x)=\sqrt{x}$

We need to find the value of $(f\circ g)(1)$ .

$(f\circ g)(1)=f(g(1))$ $[\because (f\circ g)(x)=f(g(x))]$

$(f\circ g)(1)=f(\sqrt{1})$ $[\because g(x)=\sqrt{x}]$

$(f\circ g)(1)=f(1)$

$(f\circ g)(1)=(1)^2-1$ $[\because f(x)=x^2-1]$

$(f\circ g)(1)=1-1$

$(f\circ g)(1)=0$

The value of $(f\circ g)(1)$ is 0.

Therefore, the correct option is A.

4 0

3 years ago

INTERPRETING EXPRESSIONS: <br> ln the expression 9x - 9, the variable is ___

podryga [215]

The variable is X .........

3 0

3 years ago

Consider an isosceles trapezoid rotated about an axis of symmetry that passes through the midpoint of the bases. the minor base

Ronch [10]

Based on the calculation, the perimeter of the horizontal cross-section is equal to 36.13 cm.

<h3>How to calculate the perimeter?</h3>

In this scenario, the resulting geometrical shape formed when the cut is made at the middle of the height of the trapezoid and then rotated is a circle.

<u>Given the following data:</u>

Minor base = 10 cm.

Major base = 13 cm.

From the middle, the diameter of this circle is given by:

D = 1/2 (10 + 13)

D = 11.5 cm.

Now, we can calculate the perimeter:

Perimeter = πD

Perimeter = 3.142 × 11.5

Perimeter = 36.13 cm.

Read more on trapezoid here: brainly.com/question/4758162

#SPJ1

3 0

2 years ago