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4 years ago

Which equation has only one solution?

Mathematics

2 answers:

kondor19780726 [428]4 years ago

4 0

Answer:

|–6x + 3| = 0

Step-by-step explanation:

|x – 5| = –1

Has no solutions since an absolute value cannot be negative

|–6 – 2x| = 8

will have two solutions a positive and a negative

|5x + 10| = 10

will have two solutions a positive and a negative

|–6x + 3| = 0

will have only one solution because we cannot set zero to positive and negative values

MatroZZZ [7]4 years ago

3 0

Answer:

|–6x + 3| = 0

Step-by-step explanation:

|x – 5| = –1

Absolute function cannot be equal to negative. so we cannot solve this absolute function

|–6 – 2x| = 8

For this absolute function we make two equations

-6-2x= 8 and -6-2x= 8. So we will get two solutions for x

|5x + 10| = 10

For this absolute function we make two equations

5x+10= 10 and 5x+10= -10. So we will get two solutions for x

|–6x + 3| = 0

For this absolute function we make two equations

-6x+3=0 and -6x+3=-0.

Both having same 0 on the right side. So we will get only one solutions for x

You might be interested in

Does a regular pentagon tessellate?

Mademuasel [1]

Answer:

No, it doesn't tessellate

Step-by-step explanation:

5 0

4 years ago

(2/3)^3x(2/3)^4 <br> write as a single power, then evaluate.

kow [346]

Answer:

$\frac{128}{2187}$

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$

$(\frac{2}{3}) ^{3}$ × $(\frac{2}{3}) ^{4}$

= $(\frac{2}{3}) ^{(3+4)}$

= $(\frac{2}{3}) ^{7}$

= $\frac{2^{7} }{3^{7} }$

= $\frac{128}{2187}$

6 0

3 years ago

Read 2 more answers

There are 5 students on the school chess team. They need to raise at least $445 for a field trip. Their advisor says they have r

lara31 [8.8K]

Answer: he was wrong. Each student will have to pay $76.54 at least

Step-by-step explanation:

They need to raise at least $445 for a field trip. This means that the amount to be raised should be greater than or equal to $445

Their advisor says they have raised 14% of the funds so far. This means that the amount that they have raised so far is

14/100 × 445 = 0.14×445=$62.3

The amount of money left for them to raise is total amount of money needed - 14% that they have raised so far. It becomes

445 - 62.3 = $382.7

she wants each of them to raise an equal share of the money still needed. There are 5 students on the school chess team. This means that 5 students would be raising $382.7 equally.

The leat amount of money, m that each student will have to pay is

m = 382.7/5=76.54

He solves his inequality and says the solution is m?$12.46. He got it wrong

6 0

3 years ago

=5+100+20 in number form

zlopas [31]

125
so 5+20= 25
then you add that to 100 then you would get 125

6 0

3 years ago

Read 2 more answers

A quadrilateral has two angles that measure 222° and 81°. The other two angles are in a ratio of 6:13. What are the measures of

hram777 [196]

$\sf\huge\underline{\star Solution:-}$

$\rightarrow$ <u>Ratio of two angles are 6:13.</u>

So, let the one angle be $\sf{6x}$ and another be $\sf{13x.}$

As we know that,

Sum of all interior angles of a quadrilateral = $\sf\pink{360°.}$

So let's sum up the given angles,

$\rightarrow$ $\sf{222°+81°+6x+13x \:=\: 360°}$

$\rightarrow$ $\sf{303+19x \:=\: 360°}$

$\rightarrow$ $\sf{19x \:=\: 360-303}$

$\rightarrow$ $\sf{19x \:=\: 57}$

$\rightarrow$ $\sf{x \:=\: \frac{19}{57}}$

$\rightarrow$ $\sf{x \:=\: 3}$

Hence, $\sf{x \:=\: 3}$

So, First angle $\sf{= \:6x\: = \:6×3 \:=}$ $\sf\purple{18°.}$

Second angle $\sf{= \:13x\: = \:13×3 \:=}$ $\sf\purple{39°.}$

_________________________________

Hope it helps you:)

3 0

3 years ago