1. N is a midpoint of the segment KL, then N has coordinates
2. To find the area of △KNM, the length of the base MK is 2b, and the length of the height is a. So an expression for the area of △KNM is
3. To find the area of △MNL, the length of the base ML is 2a and the length of the height is b. So an expression for the area of △MNL is
4. Comparing the expressions for the areas you have that the area 
is equal to the area 
. This means that the segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas.
Answer:
h = -7
Step-by-step explanation:
- 8 ÷ 2 = 4
- Plug 4 in: -3 = h + 4
- Subtract 4 from each side, so it now looks like this: -7 = h
I hope this helps!
Answer:
for the first one it's going to be -30 and the second one is 10
Answer:
selected variable divided by total
variables
4/29
This is all a bit complicated so try and stick with me on this one!
This one is the first problem in the first picture! a + 2 / a^2 + a - 1 / a + 1/ -a^2 - 2a - 1
= a^4 + a^3 - a^2 - a / -a^5 - 3a^4 - 3a^3 - a^2
= -a^3 - a^2 + a + 1 / a^4 + 3a^3 + 3a^2 + a
= -a^3 - a^2 + a + 1/ a^4 + 3a^3 + 3a^2 + a
= (-a - 1) (a + 1) (a - 1) / a(a+ 1) (a + 1) (a + 1)
= -a + 1 / a^2 + a
The second problem in the first picture! 3x / y + 3x - y^2 / 3xy - 9x^2 + y^2 + 9x^2 / y^2 - 9x^2
= -81x^4y + 18x^2y^3 - y^5 / 243x^5 - 54x^3y^2 + 3xy^4
This one is for the last picture! 4y^2 + 4y + 1 / 4y - 8y^2 - 4y^2 + 1 / 4y + y
= 16y^3 + 24y^2 / -32y^3 + 16u^2
= 16y + 24 / -32y + 16
= 2y + 3 / -4y + 2
I hope this was helpful!!!
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