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NNADVOKAT [17]
3 years ago
15

Which of the following is the main of the set of data below? 30, 29, 28, 30, 24, 12, 26, 33, 25, 23

Mathematics
1 answer:
Marianna [84]3 years ago
3 0

Answer:

The mean of the data is 26.

Step-by-step explanation:

Consider the provided data:

30, 29, 28, 30, 24, 12, 26, 33, 25, 23

Mean can be calculated as:

The average of all the data in a set.

x=\frac{\Sigma x_{i}}{n}

Therefore,

x=\frac{30+29+28+30+24+12+26+33+25+23}{10}

x=\frac{260}{10}

x=26

Thus, the mean of the data is 26.

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Lamar is writing a coordinate proof to show that a segment from the midpoint of the hypotenuse of a right triangle to the opposi
Zanzabum

1. N is a midpoint of the segment KL, then N has coordinates

\left(\dfrac{x_K+x_L}{2},\dfrac{y_K+y_L}{2} \right) =\left(\dfrac{0+2a}{2},\dfrac{2b+0}{2} \right) =(a,b).

2. To find the area of △KNM, the length of the base MK is 2b, and the length of the height is a. So an expression for the area of △KNM is

A_{KMN}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2b\cdot a=ab.

3. To find the area of △MNL, the length of the base ML is 2a and the length of the height is b. So an expression for the area of △MNL is

A_{MNL}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2a\cdot b=ab.

4. Comparing the expressions for the areas you have that the area A_{KMN} is equal to the area A_{MNL}. This means that the segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas.

6 0
3 years ago
Read 2 more answers
Solve the equation. −3=h+8÷2 h=?
Nimfa-mama [501]

Answer:

h = -7

Step-by-step explanation:

  1. 8 ÷ 2 = 4
  2. Plug 4 in: -3 = h + 4
  3. Subtract 4 from each side, so it now looks like this: -7 = h

I hope this helps!

6 0
3 years ago
What is the product of -6x3 and 2x5?
slamgirl [31]

Answer:

for the first one it's going to be -30 and the second one is 10

6 0
3 years ago
Mar 19, 1:51:44 PM
saveliy_v [14]

Answer:

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4 0
3 years ago
Please help me with algebra!<br> Don't answer if you don't know how to do it.
astra-53 [7]
This is all a bit complicated so try and stick with me on this one!

This one is the first problem in the first picture! a + 2 / a^2 + a - 1 / a + 1/ -a^2 - 2a - 1

= a^4 + a^3 - a^2 -  a / -a^5 - 3a^4 - 3a^3 - a^2

= -a^3 - a^2 + a + 1 / a^4 + 3a^3 + 3a^2 + a

= -a^3 - a^2 + a + 1/ a^4 + 3a^3 + 3a^2 + a

= (-a - 1) (a + 1) (a - 1) / a(a+ 1) (a + 1) (a + 1)

= -a + 1 / a^2 + a


The second problem in the first picture! 3x / y + 3x - y^2 / 3xy - 9x^2 + y^2 + 9x^2 / y^2 - 9x^2

= -81x^4y + 18x^2y^3 - y^5 / 243x^5 - 54x^3y^2 + 3xy^4


This one is for the last picture! 4y^2 + 4y + 1 / 4y - 8y^2 - 4y^2 + 1 / 4y + y 

= 16y^3 + 24y^2 / -32y^3 + 16u^2

= 16y + 24 / -32y + 16

= 2y + 3 / -4y + 2

I hope this was helpful!!!

Please remember to rate/thank/mark as brainliest if you see fit! (:



3 0
3 years ago
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