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goldenfox [79]
3 years ago
10

Norma's retirement party will cost $24 if she invites 12 guests. If there are 13 guests, how much will Norma's retirement party

cost? Solve using unit rates.
Mathematics
2 answers:
blagie [28]3 years ago
8 0

Answer:

If there are 13 guests, it would cost Norma $26

Step-by-step explanation:

Since 12 guest equals 24 dollars all you have to do is divide 24/12 which would give you 2dollars. this means that she has to pay 2 dollars per guest. Multiply 13 becuase you want to know how much money it would cost with 13 guests and you get 26 dollars. Hope this helps.

Oxana [17]3 years ago
6 0

Answer:

It'll cost $26 !

Step-by-step explanation:

if you set it up like this;

\frac{13}{x}= \frac{12}{24}

you can see a few ways of solving this !

one way is cross multiplication .

13 x 24 = 312

312 / 12 = 26

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The sodium content of a popular sports drink is listed as 200 mg in a 32-oz bottle. Analysis of 20 bottles indicates a sample me
julia-pushkina [17]

Answer:

The sample does not contradicts the manufacturer's claim.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 200 mg

Sample mean, \bar{x} = 211.5 mg

Sample size, n = 20

Alpha, α = 0.05

Sample standard deviation, s = 18.5 mg

a) First, we design the null and the alternate hypothesis  for a two tailed test

H_{0}: \mu = 200\\H_A: \mu \neq 200

We use Two-tailed t test to perform this hypothesis.

b) Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} } Putting all the values, we have

t_{stat} = \displaystyle\frac{211.5 - 200}{\frac{18.5}{\sqrt{20}} } = 2.7799

c) Now,

t_{critical} \text{ at 0.05 level of significance, 19 degree of freedom } = \pm 2.0930

Since, the calculated t-statistic does not lie in the range of the acceptance region(-2.0930,2.0930), we reject the null hypothesis.

Thus, the sample does not contradicts the manufacturer's claim.

d) P-value = 0.011934

Since the p-value is less than the significance level, we reject the null hypothesis and accept the alternate hypothesis.

Yes, both approach the critical value and the p-value approach gave the same results.

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3 years ago
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ANEK [815]

\huge\colorbox{red}T\colorbox{orange}h\colorbox{yellow}a\colorbox{green}n\colorbox{blue}k\colorbox{purple}s

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Answer:a

Step-by-step explanation:

throughout the table it is presented that the answer, A, is correct becuase within the percentages is is obvious that a is correct.

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Answer:

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Check work:

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vfiekz [6]
The answer is b. I hope this helps.
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