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hoa [83]
3 years ago
9

Find BC please in the picture

Mathematics
1 answer:
tatiyna3 years ago
7 0

B. 25 Km. The measure of BC is 25 km.

The easiest way to solve this problem is using the cosine theorem c = √a²+b²-2ab*cos A.

BC = √AC²+AB²-2(AC)(AB)*cos A

BC = √(21km)²+(14km)²-2(21km)(14km)*cos 89°

BC = √441km²+196km²-588km²*(0.017)

BC =√637km²-10.26km²

BC = √636.74km²

BC = 25.03km ≅ 25

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If X and Y are distinct digits such that the eight-digit number 7448X24Y is divisible by both 8 and 9, then find X - Y.
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The value of X - Y such that the eight-digit number 7448X24Y is divisible by both 8 and 9 is 7

<h3>How to determine the distinct digits X and Y?</h3>

The eight-digit number is given as:

7448X24Y

Also, from the question

The number is divisible by 8 and 9

When a number is divisible by 8, then the last three digits of that number would be divisible by 8.

When a number is divisible by 9, the sum of the digits of the number would be divisible by 9.

So, we have:

24Y is divisible by 8

The possible value of Y from the above statement is 0

This is so because 240 is divisible by 8

The sum of the digits of the number would be divisible by 9.

This means that:

7 + 4 + 4 + 8 + X + 2 + 4 + Y = 29 + X + Y

Substitute 0 for Y

29 + X + Y = 29 + X + 0

Evaluate the sum

29 + X + Y = 29 + X

36 is divided by 9

So, we have

29 + X = 36

Subtract 29 from both sides of the equation

X = 7

So, we have

X = 7 and Y = 0

X - Y is calculated as:

X - Y = 7 - 0

Evaluate the difference in the above equation

X - Y = 7

Hence, the value of X - Y such that the eight-digit number 7448X24Y is divisible by both 8 and 9 is 7

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brainly.com/question/26856218

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