Question

Write the equation of the line perpendicular to 2x-3y=12 which passes through the point (16,-7).

Answer 1

Y= mx+b

(16, -7) = (x,y)

2(16) - 3y = 12
32 - 3y = 12
32 - 12 = 3y
20/3 = y
6.6 = y

2x-3(-7) = 12
2x+21 = 12
2x = 12 - 21
x = -9/2

Insert the values into y = mx + b
solve for m and then solve for b