A disc of unit radius is tossed at random onto a large rectangular floor, which is tiled with $4 \times 6$ tiles. Find the proba bility that the disc is contained entirely in a rectangular tile (and does not intersect the border between two tiles).
1 answer:
Answer:
1/3
Step-by-step explanation:
In order for the disc to be entirely contained in a rectangular tile, its center must be at least 1 unit from the nearest edge. Which means there's a 2 by 4 region that the center can lie in.
So the probability is (2×4) / (4×6) = 8/24 = 1/3.
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Answer:
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Answer:
d. 11
Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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