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solong [7]
3 years ago
7

How many students were surveyed about their numbers of visits to the pool last summer?

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
4 0

Answer:

28 students were surveyed about their number of visits to the pool last summer.

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This is part 2 of my question! but the questions are marked as odds for this part, which is part 2.
Yakvenalex [24]

19) 15 <= 9 + 3x

15) x = 23,24,25

17) x <= 115

9) Second line

11) g > 20, don't fill in dot, any number greater than 20

1) -3 + h<= 3.4

3) No, x > -2

5) x > 14, don't fill in dot, any number greater than 14

7) k<=20, fill in dot, 20 or any larger number

(took me while to type this out lol cause on mobile)

5 0
2 years ago
Please help me find the total area of the composite figure below (geometry)
Akimi4 [234]

Answer:

lw + \frac{1}{2} × π × (\frac{l}{2} )^{2} ⇒ Answer D is correct

Step-by-step explanation:

First, let us find the area of the semi-circle.

Area = \frac{1}{2} × π × r²

<u>Given that,</u>

diameter of the semi-circle is ⇒ <em>l</em>

∴ radius ⇒ <em>l / 2</em>

<u>Let us find it now.</u>

Area = \frac{1}{2} × π × r²

Area =  \frac{1}{2} × π × (\frac{l}{2} )^{2}

<u>                                                     </u>

Secondly, let us find the area of the rectangle.

Area = length × width

<u>Given that,</u>

length ⇒ <em>l</em>

width ⇒ w

<u>Let us find it now.</u>

Area = length × width

Area = l ×w

Area = lw

<u>                                                      </u>

And now let us <u>find the total area.</u>

Total area =  Area of the rectangle + Area of the semi - circle

Tota area = lw + \frac{1}{2} × π × (\frac{l}{2} )^{2}

8 0
2 years ago
Is 9 greater then -8?
Alex Ar [27]

Answer:

Yes. Bc 8 have a negative sign infront of it so 9 greater

4 0
3 years ago
Read 2 more answers
Solve the following equation for x<br><br> 10=2-4(ax-3)
likoan [24]

Answer:

\large\boxed{x=\dfrac{1}{a}}

Step-by-step explanation:

2-4(ax-3)=10\qquad\text{subtract 2 from both sides}\\\\-4(ax-3)=8\qquad\text{divide both sides by (-4)}\\\\\dfrac{-4(ax-3)}{-4}=\dfrac{8}{-4}\\\\ax-3=-2\qquad\text{add 3 to both sides}\\\\ax-3+3=-2+3\\\\ax=1\qquad\text{divide both sides by}\ a\neq0\\\\x=\dfrac{1}{a}

7 0
3 years ago
Solve the following equation algebraically:
Gre4nikov [31]

Answer:

\boxed{\sf \ \ \ answer \ b. \ \ +5 \ \ \ }

Step-by-step explanation:

Hello

let's assume that we are looking for x >=0

4x^2=100  \dfrac{4x^2}{4}=x^2=\dfrac{100}{4}=25\\\sqrt{x^2}=25\\ |x| = 5  x = 5 \ or \ x=-5

Let's assume that we are looking for x>=0

so the correct answer is 5

8 0
3 years ago
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