Answer:
There is not convincing evidence at the a = 0.05 significance level that the true mean service time during the early morning shift is less than 4 minutes
Step-by-step explanation:
The null hypothesis is:

The alternate hypothesis is:

The test statistic is:

In which X is the sample mean,
is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
From a random sample of 41 orders, the mean time was 3.75 minutes with a standard deviation of 1.2 minutes.
This means that 
The test-statistic is:



has a pvalue of 0.0918, looking at the z-table.
0.0918 > 0.05, which means that the null hypothesis is accepted, and that there is not convincing evidence at the a = 0.05 significance level that the true mean service time during the early morning shift is less than 4 minutes
95/100 = 0.95 <== if she missed 5 out of 95, then she got 95 out of 100
Answer:
monomial
Step-by-step explanation:
Answer:
did you scam me? because you didn't answer my question at all