Please help, question in photo
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Answer:
A. Initially, there were 12 deer.
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. After 15 years, there will be 410 deer.
D. The deer population incresed by 30 specimens.
Step-by-step explanation:
The amount of deer that were initally in the reserve corresponds to the value of N when t=0
A. Initially, there were 12 deer.
B.
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C.
C. After 15 years, there will be 410 deer.
D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:
ΔN=N(15)-N(10)
ΔN=410 deer - 380 deer
ΔN= 30 deer.
D. The deer population incresed by 30 specimens.
Answer:
The equilibrium quantity is 26.4
Step-by-step explanation:
Given
Required
Determine the equilibrium quantity
First, we need to determine the equilibrium by equating Qd to Qs
i.e.
This gives:
Collect Like Terms
Solve for P
This is the equilibrium price.
Substitute 2.4 for P in any of the quantity functions to give the equilibrium quantity:
<em>Hence, the equilibrium quantity is 26.4</em>