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3 years ago

Which linear function has the same y-intercept as the one that is represented by the graph?

Mathematics

2 answers:

artcher [175]3 years ago

7 0

I think the answer is y=2x+3

valina [46]3 years ago

3 0

Answer: D

Step-by-step explanation:

The last one

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Rewrite the following logarithmic expression as an exponential expression

Mumz [18]

$\huge{ \mathrm{ \underline{ Answer }\: \: ✓ }}$

The logarithmic expression for the given exponential expression is :

$\large\boxed{ \mathrm{ log_{4}(b )= a}}$

_____________________________

$\mathrm{ ☠ \: TeeNForeveR \: ☠}$

4 0

3 years ago

2-(-4)/0-2 What is the answer?

Gnoma [55]

Answer:

the would be m=4

Step-by-step explanation:

7 0

2 years ago

In ΔXYZ, ∠Y=90° and ∠X=73°. ∠ZWY=80° and XW=80. Find the length of ZY to the nearest 100th.

lawyer [7]

Answer:

Solution given:

Y=90°

∠X=73°.

∠ZWY=80°

and XW=80.

ZY=?

We know that

In right angled triangle ∆ XYZ

Tan 73= $\frac{p}{h}$

3.27= $\frac{yz}{xy}$

3.27×[xy]=yz

xw+wy= $\frac{yz}{3.27}$

wy= $\frac{yz}{3.27}$ -80...........(1)

again

In right angled triangle WYZ

Tan 80= $\frac{yz}{wy}$

5.67×wy=yz

wy= $\frac{yz}{5.67}$

yz=5.67×wy............................................(2)

Equating equation 1&2

$\frac{yz}{5.67}$ = $\frac{yz}{3.27}$ -80

$\frac{yz}{3.27}$ - $\frac{yz}{5.67}$ =80

5.67yz-3.27yz=80*5.67*3.27

2.4yz =1483.272

yz= $\frac{1483.272}{2.4}$

yz=618.03

:.y=618.03unit.the length of ZY to the nearest 100th is 618.

8 0

3 years ago

Given that the mean of a data set is 25, and the standard deviation is 5, what is the Z-score of 15?

Ber [7]

The answer is negative 2

5 0

3 years ago

Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

horsena [70]

Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is:

$P(C) = (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7\\\\P(C) = \frac{1}{729}$

D. The probability is $\frac{1}{729}$ . This number is quite close to zero. Therefore it is an unlikely bastate event.

6 0

3 years ago