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3 years ago

Algebra math word problems

Mathematics

1 answer:

levacccp [35]3 years ago

3 0

7. 8n=40
n=5 bracelets
8. 20g=300
g=15 rounds of golf

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NEED HELP ASAP

mezya [45]

Answer:

5, 3

Step-by-step explanation:

correct on edge2020

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3 years ago

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No link or bot answer the question

Roman55 [17]

It’s c bc the square root of 9 is 3, while square root of 2 is not a clean answer

7 0

2 years ago

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There are a total of 64 students in a drama club and a yearbook club. The drama club has 10 more students than the yearbook club

ivolga24 [154]

Answer:

The system of equations are $x+y=64$ and $x=y+10$

Step-by-step explanation:

Given : There are a total of 64 students in a drama club and a yearbook club. The drama club has 10 more students than the yearbook club.

To find : Write a system of linear equations that represents the situation.

Solution :

Let x represent the number of students in the drama club

and y represent the number of students in the yearbook club.

There are a total of 64 students in a drama club and a yearbook club.

i.e. $x+y=64$ ....(1)

The drama club has 10 more students than the yearbook club.

i.e. $x=y+10$ ....(2)

Substitute the value of (2) in (1),

$y+10+y=64$

$2y=54$

$y=\frac{54}{2}$

$y=27$

Substitute in (2),

$x=27+10$

$x=37$

Therefore, the system of equations are $x+y=64$ and $x=y+10$

8 0

3 years ago

How many liters of peroxide should be added to 12 liters of an 8% peroxide solution so that the resulting solution contains 16%

Ilia_Sergeevich [38]

Um 12 liters i would think cause you double it

6 0

3 years ago

In ΔQRS, s = 2.3 inches, ∠S=51° and ∠Q=44°. Find the area of ΔQRS, to the nearest 10th of an square inch.

postnew [5]

Answer:

Area of ΔQRS = 2.3 square inches

Step-by-step explanation:

From the given information,

<S + <Q + <R = $180^{o}$

51 + 44 + <R = $180^{o}$

95 + <R = $180^{o}$

<R = $180^{o}$ - 95

= $85^{o}$

<R = $85^{o}$

Applying the Sine rule, we have;

$\frac{q}{SinQ}$ = $\frac{r}{SinR}$ = $\frac{s}{SinS}$

Using $\frac{r}{SinR}$ = $\frac{s}{SinS}$

$\frac{r}{Sin 85}$ = $\frac{2.3}{Sin51}$

r = $\frac{2.3*Sin85}{sin51}$

= 2.9483

r = 2.9 inches

Also, $\frac{q}{SinQ}$ = $\frac{s}{SinS}$

$\frac{q}{Sin44}$ = $\frac{2.3}{Sin51}$

q = $\frac{2.3*Sin44}{Sin51}$

= 2.0559

q = 2.0 inches

From Herons formula,

Area of a triangle = $\sqrt{s(s-q)(s-r)(s-s)}$

s = $\frac{2.3 + 2.0 + 2.9}{2}$

= 3.6

Area of ΔQRS = $\sqrt{3.6(3.6-2.0(3.6-2.9)(3.6-2.3)}$

= 2.2895

Area of ΔQRS = 2.3 square inches

8 0

3 years ago

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