Question

On Monday at 1 p.M., when the ocean's surface was at an elevation of 2.2 feet, Winston went to a surf shop that was 8.2 feet above the ocean's surface. At 7 p.M. When the ocean's surface was at an elevation of -2.4 feet, Winston ate dinner at a restaurant whose deck was 10 feet above the ocean's surface.What was the distance between the deck and the ocean's surface at 1 p.M.?

Answer 1

Answer:

5.4 feet

Step-by-step explanation:

Let the reference line $A_0B_0$ represents the sea level without any elevation.

At 1 P.M. the ocean surface was at an elevation of 2.2 feet along the line $A_1B_1$ in the figure and the surf shop was  8.2 feet above of this elevated ocean's surface along the line $A_2B_2$ in the figure.

Similarly, at 7 P.M. the ocean surface was at an elevation of -2.4 feet along the line $A_3B_3$ in the figure and the deck in the restaurant was  8.2 feet above of this elevated ocean's surface along the line $A_4B_4$ in the figure.

From the figure, the distance between the deck and the ocean's surface at 1 P.M.= The distance between the lines $A_1B_1$ and $A_4B_4$.

$d= 10- (d_1+d_2)$

$=10-(2.2+2.4)$

=5.4 feet

Hence, the distance between the deck and the ocean's surface at 1 P.M. is 5.4 feet.