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2 years ago

12

Compare the decimals 17.20 and 17.2. Which comparison is correct? A. 17.20 > 17.2 B. 17.20 < 17.2 C. 17.20 = 17.2

2 answers:

MrMuchimi2 years ago

5 0

The correct answer is C. 17.20 = 17.2

vlabodo [156]2 years ago

4 0

C is correct because these numbers are exactly the same

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An oak tree cast a shadow of 14 feet. A 30 foot flagpole casts a shadow of 60 how tall the Oak tree?

Alina [70]

Answer:

7 feet

Step-by-step explanation:

Oak tree = x

14 : x as 60 : 30

Simplify the right ratio

14 : x as 2:1

Get the same first number in both ratios by multiplying 2:1 by 7

14 : x as 2(7) + 1(7)

14 : x as 14 : 7

Since the first number in each ratio is the same, we know that that x and 7 are equal

x = 7

Hope this helps, feel free to let me know if you would like a further explanation :)

5 0

2 years ago

A football team charges $30 per ticket and averages 20,000 people per game. Each person spend an average of $8 on concessions.Fo

olya-2409 [2.1K]

The ticket price that would maximize the total revenue would be $ 23.

Given that a football team charges $ 30 per ticket and averages 20,000 people per game, and each person spend an average of $ 8 on concessions, and for every drop of $ 1 in price, the attendance rises by 800 people, to determine what ticket price should the team charge to maximize total revenue, the following calculation must be performed:

20,000 x 30 + 20,000 x 8 = 760,000
24,000 x 25 + 24,000 x 8 = 792,000
28,000 x 20 + 28,000 x 8 = 784,000
26,000 x 22.5 + 26,000 x 8 = 793,000
27,200 x 21 + 27,200 x 8 = 788,000
26,400 x 22 + 26,400 x 8 = 792,000
25,600 x 23 + 25,600 x 8 = 793,600
24,800 x 24 + 24,600 x 8 = 792,000

Therefore, the ticket price that would maximize the total revenue would be $ 23.

Learn more in brainly.com/question/7271015

4 0

2 years ago

Lucy was playing a card with two friends. They were playing with a deck of 21 cards. Lucy dealt 1/3 of the deck to each person.

Rama09 [41]

If each of them got 1/3 of the deck then they would each get 7 cards

8 0

3 years ago

Read 2 more answers

A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t

11Alexandr11 [23.1K]

Answer:

<u>Question 1:</u> $dm/dt=0.2m$ <u />

<u />

<u>Question 2:</u> $m=Ae^{(0.2t)}$ <u />

<u />

<u>Question 3:</u> $m=10e^{(0.2t)}$ <u />

<u />

<u>Question 4:</u> $m=10g$ <u />

Explanation:

<u>Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m</u>

<u></u>

a) By definition: $m'=dm/dt$

b) Given: $rate=0.2m$

c) By substitution: $dm/dt=0.2m$

<u>Question 2: Find the general solution of this equation. Use A as a constant of integration.</u>

a) <u>Separate variables</u>

$dm/m=0.2dt$

b)<u> Integrate</u>

$\int dm/m=\int 0.2dt$

$ln(m)=0.2t+C$

c) <u>Antilogarithm</u>

$m=e^{0.2t+C}$

$m=e^{0.2t}\cdot e^C$

$e^C=A\\\\m=Ae^{(0.2t)}$

<u>Question 3. Which particular solution matches the additional information?</u>

<u></u>

Use the measured rate of 4 grams per hour after 3 hours

$t=3hours,dm/dt=4g/h$

First, find the mass at t = 3 hours

$dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g$

Now substitute in the general solution of the differential equation, to find A:

$m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976$

Round A to 1 significant figure:

A = 10.

<u>Particular solution:</u>

$m=10e^{(0.2t)}$

<u>Question 4. What was the mass of the bacteria at time =0?</u>

Substitute t = 0 in the equation of the particular solution:

$m=10e^{0}\\\\m=10g$

3 0

2 years ago

I need help plsss I will give u more points

lions [1.4K]

Answer:

The value of 0.9* 10² is <u>D</u><u>.</u><u>9</u><u>0</u><u>.</u>
<u>4</u><u>*</u><u>(</u><u>1</u><u>2</u><u>-</u><u>8</u><u>)</u><u>+</u><u>2</u><u>³</u>

4*4+2³
16+8
24

a.

<u>False</u><u> </u><u>:</u><u> </u><u>it</u><u> </u><u>is</u><u> </u><u>to</u><u> </u><u>add</u><u> </u><u>1</u><u>6</u><u>+</u><u>8</u>

<u>b</u><u>.</u>

<u>False</u><u> </u><u>:</u><u> </u><u>its</u><u> </u><u>8</u><u>.</u>

<u>c</u><u>.</u>

<u>True</u><u>.</u>

<u>d</u><u>.</u>

<u>False</u><u> </u><u>:</u><u> </u><u>its</u><u> </u><u>2</u><u>4</u><u>.</u>

<u>3</u><u>.</u>

<u>side</u><u> </u><u> </u> of cube [a]=2ft

volume of cube [V]=a³=2³=8ft³

<u>He</u><u> </u><u>needs</u><u> </u><u>1</u><u> </u><u>bag</u><u> </u><u>to</u><u> </u><u>buy</u><u>.</u><u>As</u><u> </u><u>its</u><u> </u><u>volume</u><u> </u><u>is</u><u> </u><u>equal</u><u>.</u>

7 0

2 years ago