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KonstantinChe [14]
3 years ago
10

Write the word form of the following decimals. 432.98

Mathematics
2 answers:
omeli [17]3 years ago
7 0

Answer: Four hundred and thirty two point nine - eight.

Step-by-step explanation:

solong [7]3 years ago
6 0

Hey there! I'm happy to help!

With the numbers before the decimal, you just say it normally. After the decimal, you just name the digits.

So, you would call this number four hundred thirty-two point nine eight.

Have a wonderful day! :D

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Triangle ABC is similar to triangle DEF. how long is EF?<br> A) 4<br> B) 10<br> C) 14<br> D) 12
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The answer is D) 12

Step-by-step explanation:

Multiple 4 by 3

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The water level in a tank decreased 8 inches in 4 minutes. The tank drains at a steady rate. What is the change in the water lev
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2 inches per minute 8÷4=2
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Imagine a pond. In it sits one lilypad, which reproduces once a day. Each of its offspring also reproduces once a day, doubling
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Answer: On the 29th day

Step-by-step explanation:

According to this problem, no lilypad dies and the lilypads always reproduce, so we can apply the following reasoning.

On the first day there is only 1 lilypad in the pond. On the second day, the lilypad from the first reproduces, so there are 2 lilypads. On day 3, the 2 lilypads from the second day reproduce, so there are 2×2=4 lilypads. Similarly, on day 4 there are 8 lilypads. Following this pattern, on day 30 there are 2×N lilypads, where N is the number of lilypads on day 29.

The pond is full on the 30th day, when there are 2×N lilypads, so it is half-full when it has N lilypads, that is, on the 29th day. Actually, there are 2^{30} lilypads on the 30th, and 2^{29} lilypads on the 29th. This can be deduced multiplying succesively by 2.  

4 0
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A pool table is 95 inches long and 51 inches wide. what is the length of the diagonal of the pool table?
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3 0
3 years ago
An open top box is to be built with a rectangular base whose length is twice its width and with a volume of 36 ft 3 . Find the d
denpristay [2]

Answer:

The dimensions of the box that minimize the materials used is 6\times 3\times 2\ ft

Step-by-step explanation:

Given : An open top box is to be built with a rectangular base whose length is twice its width and with a volume of 36 ft³.

To find : The dimensions of the box that minimize the materials used ?

Solution :

An open top box is to be built with a rectangular base whose length is twice its width.

Here, width = w

Length = 2w

Height = h

The volume of the box V=36 ft³

i.e. w\times 2w\times h=36

h=\frac{18}{w^2}

The equation form when top is open,

f(w)=2w^2+2wh+2(2w)h

Substitute the value of h,

f(w)=2w^2+2w(\frac{18}{w^2})+2(2w)(\frac{18}{w^2})

f(w)=2w^2+\frac{36}{w}+\frac{72}{w}

f(w)=2w^2+\frac{108}{w}

Derivate w.r.t 'w',

f'(w)=4w-\frac{108}{w^2}

For critical point put it to zero,

4w-\frac{108}{w^2}=0

4w=\frac{108}{w^2}

w^3=27

w^3=3^3

w=3

Derivate the function again w.r.t 'w',

f''(w)=4+\frac{216}{w^3}

For w=3, f''(3)=4+\frac{216}{3^3}=12 >0

So, it is minimum at w=3.

Now, the dimensions of the box is

Width = 3 ft.

Length = 2(3)= 6 ft

Height = \frac{18}{3^2}=2\ ft

Therefore, the dimensions of the box that minimize the materials used is 6\times 3\times 2\ ft

4 0
3 years ago
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