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Nostrana [21]
4 years ago
8

Need some help asap​

Mathematics
1 answer:
nadya68 [22]4 years ago
3 0

Answer:

A

Step-by-step explanation:

Using the trigonometric identity

sin²x + cos²x = 1, hence

cos x = \sqrt{1-sin^2x}

cosΘ = √(1 - (\frac{\sqrt{2} }{6})²

         = \sqrt{1-\frac{2}{36} }

         = \sqrt{1-\frac{1}{18} } = \sqrt{\frac{17}{18} } and

\sqrt{\frac{17}{18} } = \frac{\sqrt{17} }{3\sqrt{2} }

multiply numerator/ denominator by \sqrt{2}

= \frac{\sqrt{34} }{6} → A

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