Question

Need some help asap​

Answer 1

Answer:

A

Step-by-step explanation:

Using the trigonometric identity

sin²x + cos²x = 1, hence

cos x = $\sqrt{1-sin^2x}$

cosΘ = √(1 - ($\frac{\sqrt{2} }{6}$)²

         = $\sqrt{1-\frac{2}{36} }$

         = $\sqrt{1-\frac{1}{18} }$ = $\sqrt{\frac{17}{18} }$ and

$\sqrt{\frac{17}{18} }$ = $\frac{\sqrt{17} }{3\sqrt{2} }$

multiply numerator/ denominator by $\sqrt{2}$

= $\frac{\sqrt{34} }{6}$ → A