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Simora [160]
3 years ago
15

Factor 20mn-15n please?

Mathematics
1 answer:
ElenaW [278]3 years ago
8 0
20mn-15n  is 5n*(4m-3)
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7- Simplify each expression.<br> -8+2(-5)
postnew [5]

Answer:

-18

Remember PEMDAS.

Step-by-step explanation:

3 0
3 years ago
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Part of arianna’s earnings are based on a 5% commission rate. At the end of the day arianna earned 14.98 in commission. How much
Katarina [22]

Arianna sold for $ 299.6

<em><u>Solution:</u></em>

Given that, Part of Arianna’s earnings are based on a 5% commission rate

At the end of the day arianna earned 14.98 in commission

Therefore,

Commission earned = $ 14.98

Commission rate = 5 %

Let "x" be the amount that Arianna sell that day

Therefore, according to question,

5 % of amount earned = 14.98

5 % of "x" = 14.98

<em><u>Solve the above equation for "x"</u></em>

5 \% \times x = 14.98\\\\\frac{5}{100} \times x = 14.98\\\\5x = 14.98 \times 100\\\\5x = 1498\\\\Divide\ both\ sides\ of\ equation\ by\ 5\\\\x = 299.6

Thus arianna sold for $ 299.6

7 0
3 years ago
1 calculate the weight of a dog on the earth and on the moon if it has a mass of 28kg<br>​
Allisa [31]

To solve the problem.

W=m×g

W=28×10

W=280.

The weight of a dog on the surface of earth is 280N.

6 0
3 years ago
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Evaluate for M/NP = 10, N = -5, and P = -2
Slav-nsk [51]
Hope this helps you..!!

3 0
3 years ago
Professor Anthony calculated a chi-square statistic of 16.22 with df=8. What is the critical value of chi-square in order to tes
Pavlova-9 [17]

Answer:  The P-Value is .039337. The result is not significant at p < .01.

Step-by-step explanation:

In the following Chi square table attached, the value is of df=8 and chi square statistic value of 16.22 is found to be between (15.507, X²₀.₀₅) and    ( 17.353, X²₀.₀₂₅).

Using the table for critical value calculation:-

Df=8 Critical value for 1%= 1.646, and we calculated our value of 17.353.

We can reject is on the basis of X²calculated > X²Critical.

The outcome doesn't falls to be in 1% of the distribution.

or

We can reject it on basis that the outcome between X²₀.₀₅ and X²₀.₀₂₅ whereas the required level of upper distribution is X²₀.₀₁

5 0
3 years ago
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