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3 years ago

Examine the equation: 4x = 2 − y Which equation represents the equivalent equation in slope-intercept form?

Mathematics

2 answers:

NeX [460]3 years ago

5 0

Answer:

Step-by-step explanation:

AURORKA [14]3 years ago

4 0

Answer:

$y=-4x+2$

Step-by-step explanation:

Since, the slope intercept form of a line is,

$y=mx+c$

Here, the given equation is,

$4x=2-y$

$4x+y=2$ ( Additive property of equality )

$y=-4x+2$ ( Subtraction property of equality )

Hence, the equation that represents the equivalent equation of the given equation in slope-intercept form is,

$y=-4x+2$

First option is correct.

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Suppose that the functions r and a are defined for all real numbers x as follows. r(x)=2x-1 S(x)=5x write the expressions for (r

NeTakaya

$\boxed{(r-s)(x)=-3x-1} \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x} \\ \\ \boxed{(r+s)(-2)=-15}$

<h2>Explanation:</h2>

In this exercise, we have the following functions:

$r(x)=2x-1 \\ \\ s(x)=5x$

And they are defined for all real numbers x. So we have to write the following expressions:

First expression:

$(r-s)(x)$

That is, we subtract s(x) from r(x):

$(r-s)(x)=2x-1-5x \\ \\ Combine \ like \ terms: \\ \\ (r-s)(x)=(2x-5x)-1 \\ \\ \boxed{(r-s)(x)=-3x-1}$

Second expression:

$(r\cdot s)(x)$

That is, we get the product of s(x) and r(x):

$(r\cdot s)(x)=(2x-1)(5x) \\ \\ By \ distributive \ property: \\ \\ (r\cdot s)(x)=(2x)(5x)-(1)(5x) \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x}$

Third expression:

Here we need to evaluate:

$(r+s)(-2)$

First of all, we find the sum of functions r(x) and s(x):

$(r+s)(x)=2x-1+5x \\ \\ Combine \ like \ terms: \\ \\ (r+s)(x)=(2x+5x)-1 \\ \\ (r+s)(x)=7x-1$

Finally, substituting x = -2:

$(r+s)(-2)=7(-2)-1 \\ \\ (r+s)(-2)=-14-1 \\ \\ \boxed{(r+s)(-2)=-15}$

<h2>Learn more: </h2>

Parabola: brainly.com/question/12178203

#LearnWithBrainly

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3 years ago

A percentage is another way to write a _________________.

konstantin123 [22]

Answer:

Ratio, Decimal or Fraction

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Suppose one honeybee makes 1/12 teaspoon of honey during its lifetime. hom many honeybees are needed to make 1/2 teaspoon of hon

iris [78.8K]

Six honeybees are needed

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3 years ago

Consider the equation (x−4)(x+3)=0.

Jlenok [28]

Answer:

(1) x (x+ 3) - 4 (x +3) = 0

(2) x = 4 and x = -3

Step-by-step explanation:

given data

equation

(x−4)(x+3)=0

solution

given equation (x−4)(x+3) = 0

equation as a compound statement is

x (x+ 3) - 4 (x +3) = 0

and

two solutions to the equation are

so x (x+ 3) - 4 (x +3) = 0

x- 4 = 0 and x + 3 = 0

x = 4 and x = -3

6 0

3 years ago

6.3 The daily amount of coffee, in liters, dispensed by a machine located in an airport lobby is a random variable X having a co

dexar [7]

Answer:

a) 60% probability that on a given day the amount of coffee dispensed by this machine will be at most 8.8 liters.

b) 70% probability that on a given day the amount of coffee dispensed by this machine will be more than 7.4 liters but less than 9.5 liters

c) 50% probability that on a given day the amount of coffee dispensed by this machine will be at least 8.5 liters

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

$P(X \leq x) = \frac{x - a}{b-a}$

The probability of X being higher than x is:

$P(X > x) = 1 - \frac{x - a}{b-a}$

The probability of X being between c and d is:

$P(c \leq X \leq d) = \frac{d - c}{b - a}$

For this problem, we have that:

$a = 7, b = 10$

(a) at most 8.8 liters;

$P(X \leq 8.8) = \frac{8.8 - 7}{10 - 7} = 0.6$

60% probability that on a given day the amount of coffee dispensed by this machine will be at most 8.8 liters.

(b) more than 7.4 liters but less than 9.5 liters;

$P(7.4 \leq X \leq 9.5) = \frac{9.5 - 7.4}{10 - 7} = 0.7$

70% probability that on a given day the amount of coffee dispensed by this machine will be more than 7.4 liters but less than 9.5 liters

(c) at least 8.5 liters.

$P(X > 8.5) = 1 - \frac{8.5 - 7}{10 - 7} = 0.5$

50% probability that on a given day the amount of coffee dispensed by this machine will be at least 8.5 liters

3 0

3 years ago