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telo118 [61]
3 years ago
7

Which number is composite? 31 43 37 49

Mathematics
1 answer:
Alina [70]3 years ago
4 0

A composite number is one that can be made by multiply two numbers to each other. Since 49=7*7, 49 is a composite number.

Check:

You can check a multiplication chart, but you will see that 49 is the only one that can be multiplied by 2 numbers

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Two numbers have a ratio of 4 to 5 and the sum of the numbers is 108 what are the two numbers??
ipn [44]

Answer: 48,60

Step-by-step explanation:

4x+5x=108

9x=108

x=108/9=12

12•4=48

12•5=60

8 0
3 years ago
What is 1986÷7 please help me
sertanlavr [38]
Step 1. Set up long division 

  _______
7| 1 9 8 6

Step 2. <span>Calculate 19 ÷ 7, which is 2 with a remainder of 5.

       2
</span>  _______
7| 1 9 8 6
    1 4
_________
       5
  Step 3. Bring down 8, so that 58 is large enough to be divided by 7.

       2
  _______
7| 1 9 8 6
    1 4
_________
       5 8

Step 4. <span>Calculate 58 ÷ 7, which is 8 with a remainder of 2.

</span>       2 8
  _______
7| 1 9 8 6
    1 4
_________
       5 8
       5 6
_________
          2

Step 5. <span>Bring down 6, so that 26 is large enough to be divided by 7.

</span>      2 8
  _______
7| 1 9 8 6
    1 4
_________
       5 8
       5 6
_______
          2 6

Step 6. Calculate 26 ÷ 7, which is 3 with a remainder of 5.
   
       2 8 3
  _______
7| 1 9 8 6
    1 4
_________
       5 8
       5 6
_______
          2 6
          2 1
       ______
             5

Step 7. <span>Therefore, 1986 ÷ 7 = 283 with a remainder of 5.

823 With a remainder of 5

Done!

</span><span>Decimal Form If Needed: 283.714286</span>
6 0
3 years ago
What is the answer 4.6n+7.1n+12.8n-1.6n= ?
Alex787 [66]
The answer would be=22.9n
4 0
3 years ago
Match each set of vertices with the type of triangle they form.
Andrew [12]

Answer:  The calculations are done below.


Step-by-step explanation:

(i) Let the vertices be A(2,0), B(3,2) and C(5,1). Then,

AB=\sqrt{(2-3)^2+(0-2)^2}=\sqrt{5},\\\\BC=\sqrt{(3-5)^2+(2-1)^2}=\sqrt{5},\\\\CA=\sqrt{(5-2)^2+(1-0)^2}=\sqrt{10}.

Since, AB = BC and AB² + BC² = CA², so triangle ABC here will be an isosceles right-angled triangle.

(ii) Let the vertices be A(4,2), B(6,2) and C(5,3.73). Then,

AB=\sqrt{(4-6)^2+(2-2)^2}=\sqrt{4}=2,\\\\BC=\sqrt{(6-5)^2+(2-3.73)^2}=\sqrt{14.3729},\\\\CA=\sqrt{(5-4)^2+(3.73-2)^2}=\sqrt{14.3729}.

Since, BC = CA, so the triangle ABC will be an isosceles triangle.

(iii) Let the vertices be A(-5,2), B(-4,4) and C(-2,2). Then,

AB=\sqrt{(-5+4)^2+(2-4)^2}=\sqrt{5},\\\\BC=\sqrt{(-4+2)^2+(4-2)^2}=\sqrt{8},\\\\CA=\sqrt{(-2+5)^2+(2-2)^2}=\sqrt{9}.

Since, AB ≠ BC ≠ CA, so this will be an acute scalene triangle, because all the angles are acute.

(iv) Let the vertices be A(-3,1), B(-3,4) and C(-1,1). Then,

AB=\sqrt{(-3+3)^2+(1-4)^2}=\sqrt{9}=3,\\\\BC=\sqrt{(-3+1)^2+(4-1)^2}=\sqrt{13},\\\\CA=\sqrt{(-1+3)^2+(1-1)^2}=\sqrt 4.

Since AB² + CA² = BC², so this will be a right angled triangle.

(v) Let the vertices be A(-4,2), B(-2,4) and C(-1,4). Then,

AB=\sqrt{(-4+2)^2+(2-4)^2}=\sqrt{8},\\\\BC=\sqrt{(-2+1)^2+(4-4)^2}=\sqrt{1}=1,\\\\CA=\sqrt{(-1+4)^2+(4-2)^2}=\sqrt{13}.

Since AB ≠ BC ≠ CA, and so this will be an obtuse scalene triangle, because one angle that is opposite to CA will be obtuse.

Thus, the match is done.

4 0
4 years ago
Read 2 more answers
NEED HELP ASAP 100PT
Mnenie [13.5K]

Answer:

It is 3 square root of 7

Step-by-step explanation:

:)

7 0
3 years ago
Read 2 more answers
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