Because ABCD is a rectangle, the length of CD is 12 cm.
We need to determine the length of DE. If we can do that, then the sum of the lengths of CD and DE represents the unknown: the length of CE.
To find the length of CE, we have to "solve" the upper triangle.
Here's an outline of what to do:
1. Show that BC=AD and find the length.
2. Note that angle CAD is 60 degrees. Why?
3. Note that angle EAD is 30 degrees. Why?
4. Find the length of ED
5. Add ED and DC, that is, ED + 12 cm. This is your answer.
Please ask questions if need be.
Correct Answer:Option A. 0.01
Solution:This is a problem of statistics and uses the concept of normal distributions. We need to convert the score of 90 into z-score and then find the desired probability from standard normal distribution table.
Converting 90 to z-score:

Now we are to find the probability of z score being more than 2.33. From the z-table the probability comes out to be 0.01.
Therefore, we can conclude that the probability of class average is greater than 90 is 0.01.
Answer:
19 (using "3.14" as pi)
18.99036781...(using pi button)
Step-by-step explanation:
Formula: C=dπ
so, (59.66)=dπ
you would divide circumference (C) by pi which will get you the answers above :)
hope this helped
There’s an app called photomath, thank me later