Answer:
The maximum value of C is 68
Step-by-step explanation:
we have the following constraints
----> constraint A
----> constraint B
----> constraint C
----> constraint D
Find out the area of the feasible region, using a graphing tool
The vertices of the feasible region are
(0,0),(5,19),(5,0)
see the attached figure
To find out the maximum value of the objective function C, substitute the value of x and the value of y of each vertex in the objective function and then compare the results
![C=6x+2y](https://tex.z-dn.net/?f=C%3D6x%2B2y)
For (0,0) -----> ![C=6(0)+2(0)=0](https://tex.z-dn.net/?f=C%3D6%280%29%2B2%280%29%3D0)
For (5,19) -----> ![C=6(5)+2(19)=68](https://tex.z-dn.net/?f=C%3D6%285%29%2B2%2819%29%3D68)
For (5,0) -----> ![C=6(5)+2(0)=30](https://tex.z-dn.net/?f=C%3D6%285%29%2B2%280%29%3D30)
therefore
The maximum value of C is 68
Answer:
It is NOT a function
Step-by-step explanation:
I hope this helps you
30 degree = k
60 degree = k square root of 3
90 degree = 2k
hypothenus =10 =>90 degree
one leg = 5 => 30 degree
Answer:
The product of (k + 1) series starts with 3 (because k = 2) and you need 2 to be multiplied to this in order to get (n + 1)!
Therefore you need to multiply 2 and 1/2 to make it right. 2 completes the factorial and 1/2 remains.
Hope it was clear explanation.