How to solve your problem
(4−3)(−22−7−5)
(4x−3)(−2x2−7x−5)(4x-3)(-2x^{2}-7x-5)(4x−3)(−2x2−7x−5)
Simplify
1
Distribute
(4−3)(−22−7−5)
(4x−3)(−2x2−7x−5){\color{#c92786}{(4x-3)(-2x^{2}-7x-5)}}(4x−3)(−2x2−7x−5)
4(−22−7−5)−3(−22−7−5)
2
distribute
4(−22−7−5)−3(−22−7−5)
4x(−2x2−7x−5)−3(−2x2−7x−5){\color{#c92786}{4x(-2x^{2}-7x-5)}}-3(-2x^{2}-7x-5)4x(−2x2−7x−5)−3(−2x2−7x−5)
−83−282−20−3(−22−7−5)
3
−83−282−20−3(−22−7−5)
−8x3−28x2−20x−3(−2x2−7x−5)-8x^{3}-28x^{2}-20x{\color{#c92786}{-3(-2x^{2}-7x-5)}}−8x3−28x2−20x−3(−2x2−7x−5)
−83−282−20+62+21+15
4
Solution
−83−222++15
I know this looks like a lot but its just how you solve your problem.
therefor, your answer is
Solution
−83−222++15
<em>Hope this helps!</em>
<em>Have a great day!</em>
<em>-Hailey</em>
48
+14
-------
62
If you need more work:
Ones place: 8+4=12
Tens place: 40+10=50
Add up: 50+12=62
Answer:The equation to determine how much Elise will pay for a student ticket is 2x = 33
Step-by-step explanation:
Let x represent the price of one student ticket.
Elise and her dad are planning to attend the state fair and the price of an adult ticket is $21.00
The price of an adult ticket is $10.00 more than two thirds the price of a student ticket. This means that
21 = 2/3 × x + 10
The equation to determine how much Elise will pay for a student ticket would be
2x/3 + 10 = 21
2x/3 = 21 - 10 = 11
2x = 11×3 = 33
x = 33/2 = $16.5
Answer: A. The difference of the two means is significant at the 68% confidence level, so the null hypothesis must be rejected.
Step-by-step explanation:
I just got it right on PLATO, so I know it’s 100% correct.
