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Katyanochek1 [597]
3 years ago
14

What are the roots of the polynomial equation x^2+8x-48=0

Mathematics
1 answer:
____ [38]3 years ago
4 0

<span> Given polynomial x^2+8x-48 = 0</span>

<span>x^2+12x-4x-48 = 0</span>

<span>x(x+12)-4(x+12) = 0</span>

<span>(x+12)(x-4) = 0</span>

<span>x+12 = 0</span>

Subtract 12 from each side.

<span>x+12-12 = 0-12</span>

<span>x = -12</span>

<span>and x-4 = 0</span>

Add 4 to each side.

<span>x-4+4 = 0+4</span>

<span>x = 4</span>

<span>Roots are -12,4.</span>

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