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Katyanochek1 [597]
3 years ago
14

What are the roots of the polynomial equation x^2+8x-48=0

Mathematics
1 answer:
____ [38]3 years ago
4 0

<span> Given polynomial x^2+8x-48 = 0</span>

<span>x^2+12x-4x-48 = 0</span>

<span>x(x+12)-4(x+12) = 0</span>

<span>(x+12)(x-4) = 0</span>

<span>x+12 = 0</span>

Subtract 12 from each side.

<span>x+12-12 = 0-12</span>

<span>x = -12</span>

<span>and x-4 = 0</span>

Add 4 to each side.

<span>x-4+4 = 0+4</span>

<span>x = 4</span>

<span>Roots are -12,4.</span>

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Try this solution:

1. for probability of both televisions work:

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2. for probability of at least on is defective (it means, the sum = one is defective and two are defective):

P_{1d}=\frac{C^1_2C^1_8}{C^2_{10}}=\frac{4*8}{9*10}=0.3(5) - for P(1defective);

P_{2d}=\frac{C^2_2}{C^2_{10}}=\frac{2}{9*10}=0.0(2) - for P(2defective);

totaly for at least one is defective:

P_{at \ least \ 1 \ d}=P_{1d}+P_{2d}=\frac{16}{45} +\frac{1}{45} =0.3(7)

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3 years ago
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8 0
3 years ago
What is the sum of 3(x + 3) and -2(x - 5)?<br> A. X-2<br> B. x-1<br> C. X + 8<br> D. X + 19
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7 0
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A frost has caused a temporary spike in the price of orange juice. the price is now $10 a gallon. before the frost, the price wa
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3 0
3 years ago
Read 2 more answers
A solution is heated from 0°C to 100°C. Between 0°C and 50°C, the rate of temperature increase is 1.5°C/min. Between 50°C and 10
muminat

Answer:

0.6 °C/min

Step-by-step explanation:

The relationship between rates and movement is ...

time = distance/speed

Here, the "distance" is measured in °C, and the "speed" is the rate of change of temperature.

For the first half of the heating, the time required is ...

(50°C -0°C)/(1.5 °C/min) = 50/(3/2) min = 100/3 min

For the second half of the heating, the time required is ...

(100°C -50°C)/(4/10 °C/min) = 50/(4/10) = 125 min

Then the total time is ...

((100/3) +125) min = (475/3) min

And the average rate of temperature increase is ...

total temperature change / total time

= (100°C -0°C)/(475/3 min) = 300/475 °C/min = 12/19 °C/min ≈ 0.6 °C/min

4 0
2 years ago
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