Does the 5 grade part matter?

Mathematics

2 answers:

Lynna [10]3 years ago

6 0

No it doesn't and the answer is that they each get .66 of a sandwich or 2/3

spin [16.1K]3 years ago

5 0

No, its extra information

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5x – (13 – x) >_9x – 7

ad-work [718]

Answer:

x<_2

Step-by-step explanation:

first off solve this like a regular equation the >_ dosent matter till later

so basically first multiply - by 13 and -x so you get -13 and x (multiplying two negatives = a positive)

so its 5x-13+x>_9x-7

add 5x and x to get 6x-13 on one side

then you get 6x-13>_9x-7 then subtract -9x from both sides

so its now -3x-13>_-7 add 13 so you get -3x>_6

then divide both sides by -3 (when you divide an equation with a >< or <_ >_ by a negative number that sign switches) so it will now be x<_2

that your final answer hope this helps :)

6 0

3 years ago

Please help! Thank you! xx

Marianna [84]

Hi!! if you dont want to use points google graph calculator. There is a good website called Graphing calculator-symbolab Its really helpful. Good Luck!!
Go for d!!

4 0

3 years ago

7y + 4x + 4 - 2x + 8 what is the coefficient

Romashka [77]

7y 4x and 2x they all are paired with a variable

3 0

3 years ago

Please simplify this fraction c:

Liula [17]

F you just want to see the really short way, just skip down to AAAAAAAAAAAA

so, here is the long explanation
exponential properties
$x^{-m}= \frac{1}{x^m}$

don't forget pemdas
2x^2=2(x^2)

so
$\frac{2x^{-4}}{3xy}$ = $\frac{2 \frac{1}{x^4} }{3xy}= \frac{2}{3x^5y}$

AAAAAAAAAAAAAAAAAAAAAAAA
so we see
the original equatio is
$\frac{2x^{-4}}{3xy}$

remember
$\frac{ab}{cd} =( \frac{a}{c})( \frac{b}{d})$

so we can seperate the constants
$\frac{ab}{cd} =( \frac{2}{3})( \frac{x^{-4}}{xy})$

we know that the placeholders cannot affet the position of the constants unless they are grouped together which they are not

terfor the answer must have 2/3 in it

the only one that hsa that is A

ANSWER IS A

3 0

3 years ago

Read 2 more answers

Amelia launched her science fair rocket, and then backed away. The path of the rocket is given by the equation below, where y is

Mamont248 [21]

Answer:

1)The rocket hit the ground at $x = \frac{5}{4}$