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3 years ago

Not sure how to do this problem

Mathematics

1 answer:

myrzilka [38]3 years ago

5 0

First we need to write the factors of the polynomial. In order for 1, 4, and -3 to be roots, they need to be the x values that make the polynomial equal 0.

(x - 1) = 0

That would be the factor for x = 1 because when we plug 1 in for x we get 1 - 1 which equals 0.

Multiply all the factors together.

(x-1)(x-4)(x+3)=0

Now FOIL.

$(x^2-5x+4)(x+3)$

$x^3-2x^2-11x+12$

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Step-by-step explanation:

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Now, factoring $5x$ from the first two terms and 6 from the last two terms, we get:

$x^2(5x(x^2+16)+6(x^2+16))=0\\x^2(x^2+16)(5x+6)=0$

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Therefore, the values of 'x' are -1.2, 0, 0, $-4i$ or $4i$ .

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