The capacitance of the certain capacitor (C) = 28.02 nF.
<h3 /><h3>How can we calculate the value of capacitance?</h3>
To calculate the value of capacitance of the certain capacitor we are using the formula here is,
Here we are given,
K= Dielectric constant of a material by which the capacitor gap is filled with = 3.3
= The permittivity of free space =
d= The width of the gap = 0.24 mm = 0.00024m.
A= The area of the plates of the capacitor.
As we know,
A = l × b
Here we are given,
l = length of the plate = 59 cm.
b = breath of the plate = 39 cm.
So according to the formula, area of the plate is,
A = l₁ × l₂
= 59 × 39
= 2301 cm²
= 0.2301 m²
So, The area of the plates of the capacitor (A)= 0.2301
We have to find the capacitance of a certain capacitor, C.
Now we put the known values in the above equation, we can get,
Or,
Or,
Or,
Or,
From the above calculation we can conclude that, the capacitance of the certain capacitor (C) is 28.02 nF.
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