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3 years ago

What two numbers are the sum of 42,000?

2 answers:

vladimir2022 [97]3 years ago

4 0

A simple problem! To find what two numbers create a given number, subtract a number (or add a number). The number you get minus the number you added/subtracted will be equal to the target number. For example:

42000-1=41999
So that would mean 41999-(-1)=42000
You could also do:
42000+1=42001
Then that would mean 42001-1=42000. Hope this helps!

:)

faltersainse [42]3 years ago

3 0

21,000+21,000=42,000

I hope it helps

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5 1/2 is how many half cups?

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11 cups is how many 5 and a half cups is in half cups

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2 years ago

How many diagonals can be drawn from each vertex of a 15-gon?

tangare [24]

Answer:

Correct option: third one -> 12

Step-by-step explanation:

In a polygon with 'n' vertex, we can trace diagonals from one vertex to all vertices, except to the vertex chosen and the two adjacent vertices (because we would have sides and not diagonals), so we would have 'n - 3' diagonals.

If we have a polygon with 15 vertex, the number of diagonals from one vertex is 15 - 3 = 12.

Correct option: third one

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2 years ago

Trapezoid WKRP was translated 4 units to the left and 5 units up on a coordinate grid to create trapezoid W’K’R’P’. Which rule d

saw5 [17]

The rule used to describe this transformation is (x, y)→(x - 4, y + 5)

<h3>Transformation</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformation are<em> rotation, reflection, translation and dilation.</em>

If a point A(x, y) is translated a units left and b units up. the new point is at A'(x - a, y + b)

Given Trapezoid WKRP was translated 4 units to the left and 5 units up on a coordinate grid to create trapezoid W’K’R’P’. The rule is given by:

(x, y)→(x - 4, y + 5)

The rule used to describe this transformation is (x, y)→(x - 4, y + 5)

Find out more on Transformation at: brainly.com/question/1462871

3 0

2 years ago

For <img src="https://tex.z-dn.net/?f=e%5E%7B-x%5E2%2F2%7D" id="TexFormula1" title="e^{-x^2/2}" alt="e^{-x^2/2}" align="absmiddl

nevsk [136]

I'm assuming you're talking about the indefinite integral

$\displaystyle\int e^{-x^2/2}\,\mathrm dx$

and that your question is whether the substitution $u=\dfrac x{\sqrt2}$ would work. Well, let's check it out:

$u=\dfrac x{\sqrt2}\implies\mathrm du=\dfrac{\mathrm dx}{\sqrt2}$
$\implies\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt2\int e^{-(\sqrt2\,u)^2/2}\,\mathrm du$
$=\displaystyle\sqrt2\int e^{-u^2}\,\mathrm du$

which essentially brings us to back to where we started. (The substitution only served to remove the scale factor in the exponent.)

What if we tried $u=\sqrt t$ next? Then $\mathrm du=\dfrac{\mathrm dt}{2\sqrt t}$ , giving

$=\displaystyle\frac1{\sqrt2}\int \frac{e^{-(\sqrt t)^2}}{\sqrt t}\,\mathrm dt=\frac1{\sqrt2}\int\frac{e^{-t}}{\sqrt t}\,\mathrm dt$

Next you may be tempted to try to integrate this by parts, but that will get you nowhere.

So how to deal with this integral? The answer lies in what's called the "error function" defined as

$\mathrm{erf}(x)=\displaystyle\frac2{\sqrt\pi}\int_0^xe^{-t^2}\,\mathrm dt$

By the fundamental theorem of calculus, taking the derivative of both sides yields

$\dfrac{\mathrm d}{\mathrm dx}\mathrm{erf}(x)=\dfrac2{\sqrt\pi}e^{-x^2}$

and so the antiderivative would be

$\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt{\frac\pi2}\mathrm{erf}\left(\frac x{\sqrt2}\right)$

The takeaway here is that a new function (i.e. not some combination of simpler functions like regular exponential, logarithmic, periodic, or polynomial functions) is needed to capture the antiderivative.

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2 years ago

A tennis ball travels at a speed of 120 miles per hour. what is the rate in feet per second?

LUCKY_DIMON [66]

Answer:176

Step-by-step explanation:

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3 years ago