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Hunter-Best [27]

4 years ago

8

A flagpole flying the Ohio state flag is 9/10 the height of a 30-foot-tall flagpole that is flying the U.S. Flag. What is the he

ight (h) in feet of the flagpole flying the Ohio state flag?

1 answer:

Oksanka [162]4 years ago

5 0

The answer to this problem is 27

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I cant delete things so I guess I'll do this instead

Alex777 [14]

Answer:

huh?

Step-by-step explanation:

7 0

3 years ago

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Find Y. Round to the nearest tenth. Z 17 ft 8 ft X 16 ft Y Y= [?]° Law of Cosines: c2 = a + b2 - 2ab cos C

ludmilkaskok [199]

Answer:

27.8

Step-by-step explanation:

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3 years ago

Jose's school spent $1284 on 9 sticksof memory and a new hard drive. The hard drive cost $168. Which is the reasonable estimate

vekshin1

It would be 1284 divided by 9 and then u round it which is 1284 / 9 =142.666 which can be rounded up to 140 or 143

5 0

4 years ago

Let f be defined by the function f(x) = 1/(x^2+9)

riadik2000 [5.3K]

(a)

$\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}$

Substitute <em>x</em> = 3 tan(<em>t</em> ) and d<em>x</em> = 3 sec²(<em>t </em>) d<em>t</em> :

$\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt$

$=\displaystyle \frac13 \lim_{b\to\infty}\left(\arctan\left(\frac b3\right)-\arctan(1)\right)=\boxed{\dfrac\pi{12}}$

(b) The series

$\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}$

converges by comparison to the convergent <em>p</em>-series,

$\displaystyle\sum_{n=3}^\infty\frac1{n^2}$

(c) The series

$\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}$

converges absolutely, since

$\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}$

That is, ∑ (-1)ⁿ (<em>n</em> ² + 9)/<em>e</em>ⁿ converges absolutely because ∑ |(-1)ⁿ (<em>n</em> ² + 9)/<em>e</em>ⁿ| = ∑ (<em>n</em> ² + 9)/<em>e</em>ⁿ in turn converges by comparison to a geometric series.

5 0

3 years ago

PLEASE HELP ME THIS IS DUE TODAY AND I AM DEPRESSED ( uhm look at photo )

Anuta_ua [19.1K]

Answer:

C. 19

B. 47

C. 12

C. 10

C. -8

Step-by-step explanation:

for each equation you take the number given, input it as the value of the variable, and evaluate the equation

hopefully this helps :)

4 0

3 years ago