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Hunter-Best [27]
3 years ago
8

A flagpole flying the Ohio state flag is 9/10 the height of a 30-foot-tall flagpole that is flying the U.S. Flag. What is the he

ight (h) in feet of the flagpole flying the Ohio state flag?
Mathematics
1 answer:
Oksanka [162]3 years ago
5 0
The answer to this problem is 27
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Georgia has a budget of $8 for a new notebook. She wants to spend within $5 of her budget, so she uses the equation 5 = |8 – x|
siniylev [52]

Answer:

Minimum: 3

Maximum: 13

Step-by-step explanation:

Georgia uses the equation

5 = |8 – x| to find the maximum and minimum values.

We solve the equation for x.

5 =  |8 - x|

By the definition of the absolute value function, we must have:

- 5 = 8 - x \: or \: 5 = 8 - x

We subtract 8 from both sides to get:

- 5 - 8 =  - x \: or \: 5 - 8 =  - x

- 13 =  - x \: or \:  - 3 =  - x

This simplifies to:

13 =  x \: or \:  3 = x

Therefore the minimum value is 3 and maximum is 13

5 0
3 years ago
The frequency table shows the favorite college football teams of middle school students.What fraction of the students chose soon
masya89 [10]
The fraction would be 5/20=1/4=.25 in decimal form.

4 0
2 years ago
Read 2 more answers
Find the equation of the line<br> Use exact numbers
GaryK [48]
Your Y intercept is 5
Y= mx + 5
Rises -5 / runs 2.5 so
Y= -2x + 5

8 0
2 years ago
What is 25/6 times 2
Darya [45]
25/6 converts to 4 1/6 so 
4 1/6 x 2 = 8 1/3 
8 1/3 is your answer :)
6 0
3 years ago
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This question is down below. The picture attached below. <br> Thanks.
Ostrovityanka [42]

The vendor has to sell 88 gingerbread houses to earn a profit of $665.60 and there is no chance that the vendor will earn $1500.

Given an equation showing profits of A Christmas vendor as

P=-0.1g^{2}+30g-1200.

We have to find the number of gingerbread houses that the vendor needs to sell in order to earn profit of $665.60 and $1500.

To find the number of gingerbread houses we have to put P=665.60 in the equation given which shows the profit earned by vendor.

665.60=-0.1g^{2}+30g-1200

0.1g^{2}-30g+1200+665.60=0

0.1g^{2}-30g+1865.60=0

Divide the above equation by 0.1.

g^{2}-300g+18656=0

Solving for g we get,

g=[300±\sqrt{(300)^{2}-4*1*18656 }]/2*1

g=[300±\sqrt{90000-74624}]/2

g=[300±\sqrt{15376}]/2

g=(300±124)/2

g=(300+124)/2       , g=(300-124)/2

g=424/2,  g=176/2

g=212,88

Because 212 is much greater than 88 so vendor prefers to choose selling of 88 gingerbread houses.

Put the value of P=1500 in equation P=-0.1g^{2}+30g-1200.

-0.1g^{2}+30g-1200=1500

0.1g^{2}-30g+1500+1200=0

0.1g^{2}-30g+2700=0

Dividing equation by 0.1.

g^{2}-300g+27000=0

Solving the equation for finding value of g.

g=[300±\sqrt{300^{2} -4*1*27000}]/2*1

=[300±\sqrt{90000-108000}] /2

=[300±\sqrt{-18000}]/2

Because \sqrt{-18000} comes out with an imaginary number so it cannot be solved for the number of gingerbread houses.

Hence the vendor has to sell 88 gingerbread houses to earn a profit of $665.60 and there is no chance that the vendor will earn $1500.

Learn more about equation at brainly.com/question/2972832

#SPJ1

7 0
1 year ago
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