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MA_775_DIABLO [31]
3 years ago
6

I need help with this math problem ​

Mathematics
2 answers:
aalyn [17]3 years ago
7 0
Yes, try the link above
Novay_Z [31]3 years ago
3 0

Answer:

Go on Desmos

Step-by-step explanation:

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The figure shows the front side of a purse in the shape of a trapezoid.
attashe74 [19]
For this case, what you must do is take out the area of two triangles and add it to the area of a rectangle to find the total area.
 We have then:
 Triangle area:
 A = (1/2) * ((13-9) / (2)) * (10) = 10 in ^ 2
 Rectangle area:
 A = (9) * (10) = 90 in ^ 2
 Total area:
 At = 2 * (10) + 90 = 110 in ^ 2
 answer:
 110 in²
8 0
3 years ago
Read 2 more answers
4)Without a calculator, name the zeros and sketch the graph.<br> 56.) = -2x(x-4)^2(x+3)^2
Ilia_Sergeevich [38]

Answer:

0, 4, -3

Step-by-step explanation:

replace y with 0 and then fro the sketch I recommend you tomuse desmos good luck buddie

6 0
3 years ago
Can somebody please help meee??
inysia [295]

Answer: d. He multiplied when he was supposed to divide

Step-by-step explanation:

He just multiplied across when he was supposed to divide (or cross multiply) to find the unit rate :)

8 0
3 years ago
Which ordered pair makes both inequalities true?
Tatiana [17]

The ordered pair which makes both inequalities true is: D. (3, 0).

<h3>How to determine ordered pair?</h3>

In Mathematics, an inequality can be used to show the relationship between two (2) or more integers and variables in an equation.

In order to determine ordered pair which makes both inequalities true, we would substitute the points into the inequalities as follows:

At (0, 0), we have:

y > -2x + 3  

0 > -2(0) + 3

0 > 3 (false).

y < x – 2

0 < 0 - 2

0 < -2 (false)

At (0, -1), we have:

y > -2x + 3  

-1 > -2(0) + 3

-1 > 3 (false).

y < x – 2

-1 < 0 - 2

-1 < -2 (false)

At (1, 1), we have:

y > -2x + 3  

1 > -2(1) + 3

1 > -1 (true).

y < x – 2

1 < 1 - 2

1 < -1 (false)

At (3, 0), we have:

y > -2x + 3  

0 > -2(3) + 3

0 > -3 (true).

y < x – 2

0 < 3 - 2

0 < 1 (true).

Read more on inequalities here: brainly.com/question/24372553

#SPJ1

3 0
2 years ago
Find the limit as x approaches infinity of y=arccos(1+x21+2x2)y=arccos((1+x^2)/(1+2x^2))?
Katyanochek1 [597]
If x approach infinity then (x² + 1)/(2x² +1) = 1/2 then lim as x  approach infinity
lim y = arccos 1/2 = 1.047
6 0
3 years ago
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