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3 years ago

Three people build a wall in 10 days. how long would it take five people?

Mathematics

1 answer:

prohojiy [21]3 years ago

3 0

Id say about 6 days....

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F(x)=x^3−9x

klio [65]

i don’t know but you could prob use photo math. that would hell

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3 years ago

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What is the equation of the function shown in the graph?

Zanzabum

Answer:

Step-by-step explanation:

I do not now what you mean?

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3 years ago

One leg of a right triangle measures 6 inches. The remaining leg measures 6 sq 3 inches. What is the measure of the angle opposi

Setler79 [48]

“6 sq 3 inches “ ? Explain it briefly I’m trying to understand

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3 years ago

The rate of growth of profit (in millions) from an invention is approximated by Upper P prime (x )equals x e Superscript negati

Alecsey [184]

Answer:

The function is $P(x) = \frac{1}{2} e^{-x^2} +0.016$

Step-by-step explanation:

From the question we are told that

The rate of growth is $P'(x) = xe^{x} - x^2$

The total profit is $P(2) =$ $25,000

The time taken to make the profit is $x = 2 \ years$

From the question

$P'(x) = xe^{-x^2}$ is the rate of growth

Now here x represent the time taken

Now the total profit is mathematically represented as

$P(x) = \int\limits {P'(x)} \, = \int\limits {xe^{-x^2}} \,$

So using substitution method

We have that

$u = - x^2$

$du = 2xdx$

$p(x) = \int\limits {\frac{1}{2} e^{-u}} \, du$

$p(x) = {\frac{1}{2} [ e^{-u}} +c ]$

$p(x) = {\frac{1}{2} e^{-x^2}} + \frac{1}{2} c$ recall $u = - x^2$ and let $\frac{1}{2} c = Z$

At x = 2 years

$P(x) =$ $25,000

Since the profit rate is in million

$P(x) =$ $25,000 = $\frac{25000}{1000000} =$ $0.025 millon dollars

$0.025 = {\frac{1}{2} e^{-2^2}} + Z$

=> $Z = 0.025 - {\frac{1}{2} e^{-2^2}}$

$Z = 0.016$

So the profit function becomes

$P(x) = \frac{1}{2} e^{-x^2} +0.016$

5 0

3 years ago

I am driving from oakland california to erlanger kentucky. The distance is 2,364.6 miles. My gas tank gets 25 miles per gallon o

solong [7]

Answer:$1655.22

Step-by-step explanation:

The total distance from Oakland California to Erlanger Kentucky is 2,364.6 miles. The gas tank gets 25 miles per gallon on the highway. It means that total number of gallons required to cover the distance from Oakland California to Erlanger Kentucky would be

2364.6/25 = 472.92 gallons

If the gas cost $3.50 per gallon, it means that the total amount that it will cost to drive from Oakland California to Erlanger Kentucky would be

472.92 × 3.5 = $1655.22

5 0

3 years ago