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Zina [86]
3 years ago
14

Simplify the expression (x^2 + 2x + 3)(x^2 – 2x – 2)

Mathematics
2 answers:
boyakko [2]3 years ago
8 0

Answer:

x^4-3x^2-10x-6

Step-by-step explanation:

To simplify this expression we must apply the distributive property

Distributive Property

(a+b)(c+d)= ac+ad+bc+bd

Going over some rules

Law of the signs

(-)(-)=+\\(-)(+)=-\\(+)(+)=+

Powers

Ax^b.Cx^d=ACx^{(b+d)}

Simplifying

(x^2+2x+3)(x^2-2x-2)=x^4-2x^3-2x^2+2x^3-4x^2-4x+3x^2-6x-6

We add similar terms (those that have the same power)

x^4-2x^3-2x^2+2x^3-4x^2-4x+3x^2-6x-6\\x^4-3x^2-10x-6

Leto [7]3 years ago
5 0
Simplified: x^4+3x^2-10x-6 
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3 7/24 is the answer for your question
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3 years ago
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Imaginá que tenés 125 dados cúbicos del mismo tamaño ¿Cuantos dados de altura tiene el cubo de mayor tamaño que podés armar apil
kumpel [21]

Answer:

(i) Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

Step-by-step explanation:

(i) Sabemos por la Geometría Euclídea del Espacio que un cubo es un sólido regular con 6 caras cuadradas y longitudes iguales. Cada dado tiene un volumen de 1 dado cúbico y 125 dados dan un volumen total de 125 dados cúbicos.

El volumen de un cubo está dado por la siguiente fórmula:

V = L^{3}

Donde:

L - Longitud de la arista, medida en dados.

V - Volumen del cubo, medido en dados cúbicos.

Ahora, necesitamos despejar la longitud de la arista para calcular la altura máxima posible:

L = \sqrt[3]{V}

Dado que V = 125\,dados^{3}, encontramos que la altura del cubo de mayor tamaño sería:

L =\sqrt[3]{125\,dados^{3}}

L = 5\,dados

Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) El área cuadrada formada por cubos está determinada por la siguiente fórmula:

A = L^{2}

Donde:

L - Longitud de arista, medida en dados.

A - Área, medida en dados cuadrados.

Puesto que la longitud de arista se basa en un conjunto discreto, esto es, el número de dados disponibles, debemos encontrar el valor máximo de L tal que no supere 125 y de un área entera. Es decir:

L \leq 125\,dados

Si cada cubo tiene un área de 1 dado cuadrado, entonces un cuadrado conformado por 125 dados tiene un área total de 125 dados cuadrados. Entonces:

L^{2}< 125\,dados^{2}

Esto nos lleva a decir que:

L < 11.180\,dados

Entonces, la longitud máxima del cuadrado con la mayor cantidad de cubos posible es de 11 dados. El número total requerido de cubos es el cuadrado de esa cifra, es decir:

n = (11\,dados)^{2}

n = 121\,dados

Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

4 0
3 years ago
100 point reward with certified answer. 4 basic algebra questions, must show work. If the answers are wrong your response will b
ipn [44]
Y=kx
12=-4k
  k = -3

so when y = 15
y = kx
15 = -3x
  x = -5

----------------

$50 / 0.04 = $1250 (4% interest)

so
1250 * 0.06 = $75

answer
interest $75 at 6%

-----------------------------

y = kx
1/4 = 4k
k = 1/16

when x = 5
y = kx
y = 1/16(5)
y = 5/16 

-----------
y = kx
-5 = 4k
k = -5/4

direct equation
y = -5/4x

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garri49 [273]
So you have 5.36
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Hope this helps
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3 years ago
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A number is subtracted from 20 and from 17. The product of the number so obtained is 180. Find the original number
matrenka [14]

I don't really understand your question, but it think it goes like this:

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gather common terms

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x=180+37

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