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3 years ago

How do u find net force?

1 answer:

7 0

1Draw a quick sketch of the object.
2Draw an arrow showing every force acting on the object.
3<span>To calculate the net force, add any vectors acting on the same axis (x and y), making sure to pay attention to the directions.
Hope this helps :)
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A hydraulic lift has two connected pistons with cross-sectional areas 15 cm2 and 670 cm2. It is filled with oil of density 510 k

BigorU [14]

Answer:

Explanation:

Given

Cross-sectional area of two areas is

$A_1=15\ cm^2$

$A_2=670\ cm^2$

It is filled with oil of density $\rho _0=510\ kg/m^3$

mass of car place on Large area $M=1100\ kg$

Suppose a mass of m kg is placed on smaller area

According to pascal law's intensity of pressure is same at every point on Liquid

$P_1=P_2$

$\frac{F_1}{A_1}=\frac{F_2}{A_2}$

$\frac{mg}{15}=\frac{Mg}{670}$

$m=1100\times \frac{15}{670}$

$m=24.62\ kg$

4 0

3 years ago

What is a chemical energy

Papessa [141]

Chemical energy is the potential of a chemical substance to undergo a transformation through a chemical reaction to transform other chemical substances. Examples include batteries, food, gasoline, and etc.

8 0

3 years ago

You are to drive to an interview in another town, at a distance of 270 km on an expressway. the interview is at 11:15

Crazy boy [7]

<span>Time needed for drive a distance 100 km at 100 km/h: t1 =100/100 = 1 h Time needed for drive a distance 40 km at 45 km/h: t2 =40/45 =0.8 h t3 =3h 15m - 1 h- 0.8 h =1.45 h Distance to town equals: s3 =270-100-40 =130 km Least speed needed to arrive in time for the interview: v3 =130 km/1.45 h =89.65 km/h The answer is 89.65 km/h</span>

6 0

3 years ago

When checking for noncondensables inside a recovery cylinder why should the technician allow the temperature of the cylinder to

77julia77 [94]

Before taking a pressure reading, it is necessary for the technician to first allow the temperature of the cylinder to stabilize to room temperature because a comparison with a temperature-pressure chart is only valid and true when both temperature and pressure of the refrigerant are stable.

3 0

3 years ago

A playground slide is inclined 40°. If a boy with a mass of 32 kg slides down for -3meters. How much work is done by gravity on

telo118 [61]

Answer:

the work done by gravity on the boy is 604.62 J

Explanation:

Given;

distance the boy slides, d = 3 m

angle of inclination of the playground, θ = 40⁰

mass of the boy, m = 32 kg

The vertical height, h, above the ground through which the boy falls represents the height of the triangle which is the opposite side.

The distance through which the boy slides, d, represents the hypotenuse side of the right triangle.

$sin \theta = \frac{opposite }{hypotenuse} \\\\sin \theta = \frac{h}{d} \\\\h = dsin\theta\\\\h = 3 \times sin(40^0)\\\\h = 1.928 \ m$

The work done by gravity on the boy is calculated as;

W = P.E = mgh

= 32kg x 9.8m/s² x 1.928m

= 604.62 J

Therefore, the work done by gravity on the boy is 604.62 J

8 0

3 years ago