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gladu [14]
3 years ago
10

A person, whose eye has a lens-to-retina distance of 2.0 cm, can only clearly see objects that are closer than 1.0 m away. what

is the strength
Physics
1 answer:
shutvik [7]3 years ago
5 0

To calculate the strength of the eye lens, we use the formula

\frac{P}{100} = \frac{1}{f} =\frac{1}{u} +\frac{1}{v}  ( thin lens formula)

Here, u is the object distance and v is image distance.

Given, u =1 m=100cm and v = 2 cm

Therefore,

\frac{1}{f} =\frac{1}{100} + \frac{1}{2}

\frac{1}{f} = 0.01 + 0.5= 0.51 cm

Thus, strength of the eye lens is

P= \frac{100}{f} =\frac{100}{\frac{1}{0.51} } = 51 D



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Answer

given,

mass of the goalie(m₁) = 70 kg

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3 years ago
A bullet is fired vertically upward a velocity of 80m/s to what height will the bullet rise above the point of projection​,note:
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hope this helps :)

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As you move away from a positive charge distribution, the electric field:
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Answer:

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The position vector r describes the path of an object moving in the xy-plane. position vector point r(t) = ti + (ât2 + 7)j (1, 6
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We can decompose the problem on x- and y-axis.

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