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Yuki888 [10]
3 years ago
13

What is the median of 23 2 5 14 25 36 27 42 12 8 7 23 29 28 11 20 31 8 36

Mathematics
1 answer:
den301095 [7]3 years ago
3 0

Answer:

23

Step-by-step explanation:

The median is the number in the middle of the data once it is organized from least to greatest, so that is what we must do first.

2,5,7,8,8,11,12,14,20,23,23,25,27,28,29,31,36,36,42

There are 19 numbers, that means that the 10th value will be the number in the middle

This means that the median is 23

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Nat2105 [25]

Answer:  \bold{9)\ \sin \theta=\dfrac{1}{3}\qquad 10)\ \sin \theta = \dfrac{4}{5}\qquad 11)\ \cos \theta = \dfrac{\sqrt{11}}{6}\qquad 12)\ \tan \theta = \dfrac{17\sqrt2}{26}}

<u>Step-by-step explanation:</u>

Pythagorean Theorem is: a² + b² = c²   , <em>where "c" is the hypotenuse</em>

<em />

9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}

Note: 4² + (8√2)² = hypotenuse²   →   hypotenuse = 12

10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}

Note: 12² + opposite² = 20²   →   opposite = 16

11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}

Note: adjacent² + 5² = 6²   →   adjacent = √11

12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}

Note: adjacent² + 7² = (13√2)²   →   adjacent = 17

5 0
3 years ago
I don’t understand this can someone help? Please
Kobotan [32]

Answer:mkay, also yes he did

Step-by-step explanation:

1.Remove the parentheses

2.put -5z and 4z together which makes -9z(negative plus positive equals negative)

3.-9z+ -6z=-3z and 7+8=15

4.15 decided by -3=5

so yes, z=-5

7 0
3 years ago
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Dafna1 [17]
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3 years ago
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agasfer [191]

Answer:

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3 years ago
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xxTIMURxx [149]
The answer would be -1. ☺️
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