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gizmo_the_mogwai [7]
3 years ago
10

(b) Write 3*3*3*3* 3 as a single power of 3

Mathematics
2 answers:
Dominik [7]3 years ago
6 0
Answer:
3 with an exponent of 5
algol133 years ago
5 0

Answer:

3⁵

Step-by-step explanation:

3×3×3×3×3=3⁵

You have a mutiplication. The base is 3, the exponent is the count of how many 3 you have. In this multiplication 3 appears 5 times, so 3⁵.

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Can you help me with my math questions
GrogVix [38]

p^2+2(7)p+7^2=(p+7)^2


Justification:

Given:  p^2+14p+49


Split the middle term;

=p^2+7p+7p+49


Factor:

=p(p+7)+7(p+7)


=(p+7)(p+7)


=(p+7)^2


QUESTION 3a

The given expression for the area of the rectangle is  36x^2-12x+1.


This is equal to the indicated area which is 289\;in^2


This implies that


36x^2-12x+1=289


\Rightarrow (6x-1)^2=289


\Rightarrow (6x-1)(6x-1)=289


\Rightarrow l=(6x-1),w=(6x-1)



This implies that, the dimensions of the rectangle are equal;


Using the square root method, we obtain

\Rightarrow (6x-1)=\pm \sqrt{289}


\Rightarrow (6x-1)=\pm 17


\Rightarrow 6x=1\pm 17


\Rightarrow 6x=18 \:or\:6x=-16


\Rightarrow x=3 \:or\:x=-\frac{2}{3}

We discard the negative value.

The side length of this rectangle is


\Rightarrow l=(6(3)-1)=17,w=6(3)-1=17


QUESTION 3b

The given expression for the area of the rectangle is  25x^2-50x+25.


This is equal to the indicated area which is 1225\;in^2


This implies that


25x^2-50x+25=1225


25(x^2-2x+1)=1225


(5(x-1))^2=35^2


5(x-1)5(x-1)=49


\Rightarrow l=5(x-1),w=5(x-1)



This implies that, the dimensions of the rectangle are equal;


Using the square root method, we obtain

\Rightarrow 5(x-1)=\pm \sqrt{1225}


\Rightarrow 5(x-1)=\pm 35


\Rightarrow x=1\pm 7


\Rightarrow x=8 \:or\:x=-6

We discard the negative value.

The side length of this rectangle is


\Rightarrow l=5(8-1)=35,w=5(8-1)=35



QUESTION 3c

The given expression for the area of the rectangle is  49x^2-56x+16.


This is equal to the indicated area which is 289\;in^2


This implies that


49x^2-56x+16=289




(7x-4)^2=289


(7x-4)(7x-4)=289



\Rightarrow l=(7x-4),w=(7x-4)


Applying the laws of indices gives;


(7x-4)^2=17^2


This implies that;

7x-4=17


7x=21


x=3in.


The side length of this rectangle is


\Rightarrow l=7(3)-4=17\:in.,w=7(3)-4=17\:in.


Dont forget that the square is also a rectangle.





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