All categories

3 years ago

Quick answer pleaseee

Mathematics

1 answer:

Nikolay [14]3 years ago

3 0

D is the correct answer

You might be interested in

Find the value of x.

svetoff [14.1K]

Answer:

Step-by-step explanation:

1) Find the interior angle using relations of angles in straight line I.e ( sum of angles in a straight line is 180 ) and we know the sum of all the interior angle of quadrilateral is 360 degree .

2) Solve further for x.

5 0

3 years ago

8 3/4 + 9 5/9= <br> with working?

Gre4nikov [31]

8 3/4 + 9 5/9 Add 8 and 9

17 + 3*9/4*9 + 5*4/9*4 Find common denominator

17 + 27/36 + 20/36 Add

17 + 47/36 Convert into mixed fraction

17 + 1 11/36 Simplify mixed fraction

18 11/36. Answer

If you need the decimal form, it is 18.31. But other than that, the answer is 18 11/36.

4 0

3 years ago

Duane is making cookies. The recipe calls for two times as many cups of sugar as butter, two times as many cups of oats as sugar

Tamiku [17]

Answer:

6.0

Step-by-step explanation:

: (2.0+(2.0+2.0)) = 6.0

6 0

3 years ago

Extra POINTS Lila made 98 phone calls in 3 months. In the first month she made 34 calls, and in the second month she made 42 cal

Rzqust [24]

Answer:

A. 22

Step-by-step explanation:

98 - 34 - 42 is equal to 22. Or 34 + 42 os 76. Subtract 76 from 98. You get 22.

6 0

3 years ago

AYUDA CON ESTO!!! ALGUIEN PORFAVOR

Gre4nikov [31]

Answer:

Problem 1) frequency: 160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

$Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds$

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

$\frac{200}{60} = \frac{10}{3} \approx 3.33$ loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

$\frac{200}{65} = \frac{40}{13} \approx 3.08$ loops per minute

then the period is:

$\frac{13}{40} =0.325\,\,\,minutes$

Therefore runner B has the smaller period

8 0

3 years ago