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Virty [35]
3 years ago
15

Quick answer pleaseee

Mathematics
1 answer:
Nikolay [14]3 years ago
3 0
D is the correct answer
You might be interested in
Is the product of fifteen negative integers positive or negative?
enot [183]

Answer:

the sign of the product of 15 negative numbers will be negative

Step-by-step explanation:

Heya mate!!

The product of odd numbers is odd and the product of even numbers is even.

so 15 is an odd number then the sign of product is odd

Hope this helps!!!

3 0
3 years ago
Complete the table for y=1/2x-3
Readme [11.4K]

Tables are created by substitute a set of input values into the function to create outputs. The required table is as shown below

<em>x | y</em>

<em>0   -3 </em>

<em>1   -2.5</em>

<em>2   -2 </em>

<h3>Tables and values</h3>

Tables are created by substitute a set of input values into the function to create outputs

Using x = 0, 1 and 2 as the input values

Given the function

y = 1/2x - 3

If x = 0

y = 1/2(0) - 3

y = -3

If x = 1

y = 1/2(1) - 3

y = -2.5

If x = 2

y = 1/2(2) - 3

y = -2

Hence the required table is as shown below

x | y

0   -3

1   -2.5

2   -2

Learn more on tables and values here: brainly.com/question/12151322

#SPJ1

8 0
2 years ago
You sell tires for $65 each at your automotive service shop. At this price, what does it cost to purchase a set of 4 tires, not
kow [346]

Answer:

$260

Step-by-step explanation:

you multiply $65 by 4 for the set of four and the product is $260.

4 0
4 years ago
Read 2 more answers
72÷8+3.4-105÷5<br>they say the answer is 0 but don't see how.
Sidana [21]
72/8 +3*4 - 105 /5
= 9 + 12 - 21
= 21 -21
= 0
4 0
3 years ago
What is the slope of the line tangent to the curve y+2 = (x^2/2) - 2siny at the point (2,0)?
kirza4 [7]
<span>, y+2 = (x^2/2) - 2sin(y) so we are taking the derivative y in respect to x so we have dy/dx use chain rule on y so y' = 2x/2 - 2cos(y)*y'

</span><span>Now rearrange it to solve for y' y' = 2x/2 - 2cos(y)*y' 0 = x - 2cos(y)y' - y' - x = 2cos(y)y' - y' -x = y'(2cos(y) - 1) -x/(2cos(y) - 1) = y'
</span><span>we know when f(2) = 0 so thus y = 0 so when f'(2) = -2/(2cos(0)-1)
</span><span>2/2 = 1
</span><span>f'(2) = -2/(2cos(0)-1) cos(0) = 1 thus f'(2) = -2/(2(1)-1) = -2/-1 = 2 f'(2) = 2
</span>
6 0
3 years ago
Read 2 more answers
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