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mestny [16]
3 years ago
15

Can someone help me please I do not know the answer

Mathematics
1 answer:
Afina-wow [57]3 years ago
4 0
You subtract 15.50 from 47.50 
then you will get your answer it is  31
You might be interested in
5. If the tree's circumference is 141.3ft, what is its diameter?
BigorU [14]

Answer:

d ≈ 45 ft

General Formulas and Concepts:

<u>Symbols</u>

  • π (pi) ≈ 3.14

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Geometry</u>

  • Circumference of a Circle Formula: C = πd

Step-by-step explanation:

<u>Step 1: Define</u>

Circumference <em>C </em>= 141.3 ft

<u>Step 2: Solve for </u><em><u>d</u></em>

  1. Substitute in <em>C</em> [Circumference Formula]:                                                       141.3 ft = πd
  2. Substitute in π (approximation):                                                                      141.3 ft ≈ 3.14d
  3. [Division Property of Equality] Divide both sides by 3.14:                              45 ft ≈ d
  4. Rewrite:                                                                                                             d ≈ 45 ft
7 0
3 years ago
Read 2 more answers
Suppose s varies directly with t. When t=27, s=3. What is s when t=63?
adell [148]

Answer: s = 7

Step-by-step explanation:

27 is simply 9 times 3.

Thus, simply do 63/9 to get 7.

Hope it helps :)

3 0
3 years ago
Read 2 more answers
A cell phone provider classifies its customers as Low users (less than 400 minutesper month) or High users (400 or more minutes
Svet_ta [14]

Answer:

a ) See step by step explanation

b) 50%   and  50%

Step-by-step explanation:

The definition of type of user x is:

if x < 400 minutes  per month  low user

if x > 400 minutes per month  high user

The value for these states are of course yes  or no  ( the user is low or high user)

Then:

if the user is low today  xt  (0)    we have the probability of 80% ( 0,8) of have the user in the same condition and 20% (0,2) of having him or her as high user

xt = 1      

If the user is high today xt (1) is high today we have the probability of 70% ( 0,7) of having  the user in the same condition and 30% (0,3) of having him or her as high user

a) Then we construct the stochastic matrix

 Type of user

         (xt)               xt         xt+1  

      Low (0) or L   0,8        0,2

     High(1)  or H   0,3        0,7

The resulting equation system is:

xt  =  0,8* xt  +  0,2* xt+1

xt+1  = 0,3*xt + 0,7* xt+1

1  =  xt + xt+1

Solving for variables         xt+1  =  1  - xt

xt  = 0,8*xt + ( 1 - xt ) * 0,2

xt - 0,8*xt = 0,2 - 0,2xt

xt - 0,6*xt = 0,2

0,4*xt = 0,2

xt = 0,5       and     xt+1  = 0,5

b)  If in January 0,5  ( 50%) of customesr were  low user

In february  teh % of low user customer wll be

xt  =  0,8* xt  +  0,2* xt+1

0,5 = 0,8*0,5 + 0,2*xt+1

0,5 = 0,4 + 0,2 *xt+1

0,1/0,2 = xt+1        xt+1 = 0,5       or   50%

The same answer for March

7 0
3 years ago
A publisher reports that 30% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is
Ierofanga [76]

Answer:

Test statistic = - 2.29

Pvalue = 0.0110

Step-by-step explanation:

The hypothesis :

H0 : p = 0.3

H1 : p < 0.3

Test statistic :

z=pˆ−p/√p(1−p)/n

pˆ = 0.2

Z = (0.20 - 0.30) / √(0.30(1 - 0.30) / 110

Z = - 0.1 / √0.0019090

Z = - 0.1 / 0.0436931

Z = - 2.29

Test statistic = -2.29

The Pvalue :

P(Z < -2.29) = 0.0110

4 0
3 years ago
Jackson goes to the gym 0, 2, or 3 days per week, depending on work demands. The expected value of the number of days per week t
Doss [256]
So what's your question?

6 0
3 years ago
Read 2 more answers
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