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3 years ago

PLS HELP MATHH ILL GIVE BRAINLIEST, 5-6TH GRADE MATH

Mathematics

1 answer:

adell [148]3 years ago

7 0

Answer:

It is 9

Step-by-step explanation:

The outlier is the data point that differs significantly from other observations.

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What is the measurement of F?

Norma-Jean [14]

44 degrees is the answer

5 0

3 years ago

In the library at lenape elmentary school, there are 3/8 as, many fiction books as there are nonfiction books. There are 44 book

N76 [4]

Answer:

12 fiction books.

Step-by-step explanation:

Let b represent number of non-fiction books.

We have been given that in the library at Lenape elementary school, there are 3/8 as many fiction books as there are nonfiction books. So number of fiction books would be $\frac{3}{8}x$ .

We are also told that there are 44 books in school library. We can represent this information in an equation as:

$x+\frac{3}{8}x=44$

Let us solve for x.

$\frac{8x}{8}+\frac{3}{8}x=44$

$\frac{8x+3x}{8}=44$

$\frac{11x}{8}=44$

$\frac{11x}{8}\cdot \frac{8}{11}=44\cdot\frac{8}{11}$

$x=4\cdot 8$

$x=32$

Therefore, there are 32 non fiction books in the library.

Number of fiction books would be $\frac{3}{8}x\Rightarrow \frac{3}{8}*32=3*4=12$

Therefore, there are 12 fiction books in the library.

5 0

3 years ago

Mr. Cromleigh and his mom stayed at a hotel while in Vegas. If the room was 12ft by 8ft by 9ft, what is the volume of the room?

Komok [63]

Answer:

864 ft³

Step-by-step explanation:

Volume = Length * Width * Height

Substitute

Volume = 12 * 8 * 9

Volume = 864 ft³

Hope this helps :)

7 0

4 years ago

Read 2 more answers

We have 8 yards of wraping paper. if we use 2 feet for each present how many present can we wrap

kirill [66]

We can wrap 12 presents. multiply the number of yards by the feet.

3 0

4 years ago

Read 2 more answers

A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet

Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

$L_{1} = 2W_{1}$

Also, the area of the walkway of 2 feet wide is 448:

$W_{2} = 2 ft$

$A_{T} = W_{2}*L_{2} = 448 ft^{2}$

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

$A_{T} = A_{1} + A_{w}$ (1)

The area of the pool is given by:

$A_{1} = L_{1}*W_{1}$

$A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}$ (2)

And the area of the walkway is:

$A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}$ (3)

Where the length of the bigger rectangle is related to the lower rectangle as follows:

$L_{2} = 4 + L_{1} = 4 + 2W_{1}$ (4)

By entering equations (4), (3), and (2) into equation (1) we have:

$A_{T} = A_{1} + A_{w}$

$A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}$

$448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}$

$224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}$

$224 = W_{1}^{2} + 8 + 6W_{1}$

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

$L_{1} = 2W_{1} = 2*12 ft = 24 ft$

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!

8 0

3 years ago