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Lapatulllka [165]
2 years ago
6

PLS HELP MATHH ILL GIVE BRAINLIEST, 5-6TH GRADE MATH

Mathematics
1 answer:
adell [148]2 years ago
7 0

Answer:

It is 9

Step-by-step explanation:

The outlier is the data point that differs significantly from other observations.

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Can anyone pleaseee help me with this question
bija089 [108]

Answer:

3.7

Step-by-step explanation:

4(x+3.3)=28\\4x+13.2=28\\4x=28-13.2\\\\4x=14.8

x=\frac{14.8}{4} =3.7

Hope this helps

3 0
2 years ago
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Solve. <br> - 1/3b = 9<br><br> A. -3 <br> B. 3<br> C. - 27<br> D. 27
ruslelena [56]
-\dfrac{1}{3}b=9\ \ \ |multiply\ both\ sides\ by\ (-3)\\\\-3\cdot\left(-\dfrac{1}{3}b\right)=-3\cdot9\\\\\huge\boxed{b=-27}\leftarrow\boxed{C}
3 0
3 years ago
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Please help if you can!
Dima020 [189]

Answer:

m' (-2, 4)

n' (-2, 1)

o' (3, 1)

p' (3, 4)

Step-by-step explanation:

4 0
2 years ago
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HELP PLEASE!
Bas_tet [7]

Answer:

27/8

Step-by-step explanation:

3 3/8

you multiply the denominator by the whole number and then add into numerator. so

8 x 3 = 24

           24+ 3 =27

Answer= 27/8

6 0
3 years ago
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Suppose you decided to keep flipping a coin until tails came up, at which
MAVERICK [17]

Answer:

B. 6.3%

Step-by-step explanation:

For each time that the coin is tosse, there are only two possible outcomes. Either it comes up tails, or it does not. The probability of coming up tails on a toss is independent of any other toss. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Fair coin:

Equally as likely to come up heads or tails, so p = 0.5

Probability that the first tails comes up on the 4th flip of the coin?

0 tails during the first three, which is P(X = 0) when n = 3.

Tails in the fourth, with probability 0.5. So

p = 0.5P(X = 0)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

p = 0.5P(X = 0) = 0.5*(C_{3,0}.(0.5)^{0}.(0.5)^{3}) = 0.0625

0.0625 * 100 = 6.25%

Rounding to the nearest tenth of a percent, the correct answer is:

B. 6.3%

4 0
3 years ago
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