What is the value of X in the equation?

Mathematics

2 answers:

wel4 years ago

8 0

The answer would be 72. Let's look at the denominators to solve the problem. First, let's see if the denominators are equivalent or related in some type of way. 84 and 7 are related because 84 divided by 7 equals 12. Now, according to the law of proportion, the left must be equal to the right, and that concludes that in the end, the the two fractions must be equivalent. Since you have to multiply 7 by 12 to get the output of 84, multiply the top number 6 by 12 to get the answer of 72. Why I chose 72 instead of -72 is because there is already a negative sign on the right side as on the left. Another way you can do this is by cross-multiplying.

Ivan4 years ago

4 0

i think that the answer is b

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inessss [21]

Answer:

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Step-by-step explanation:

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Plot the ordered paired (4,-5) state which quadrant or on which axis the point lies

Rudiy27

Answer:

The point is in the 4th quadrant.

Explanation:

Given the ordered pair(4, -5), we have that x = 4 and y = -5. Plotting this point, we'll have;

Note that quadrants are labelled in an anti-clockwise direction with the top right portion of the graph as the 1st quadrant. Looking at the plotted point, we can see that it i in the 4th quadrant.

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1 year ago

Find the midsegment of the triangle which is parallel to CA.

Nataliya [291]

Answer:

$\pmb{ \pink{QUESTION�}}$

Find the midsegment of the triangle which is parallel to CA.

$\pmb{ \pink{ANSWER:-}}$

Tip

A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
If two segments are congruent, then they have the same length or measure.In other words, congruent sides of a triangle have the same length.

$\frak{Explanation:-}$

We have to find the segment which is parallel to CA.

From the given data,

The segment EG is the midsegment of the triangle $\triangle$ ABC.

So we have,

A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment has two special properties. It is always parallel to the third side.

$\implies\rm{midsegment \: EG \: parallel \: to \: CA}$