Wel have to use the Pythagorean theorem (a^2) + (b^2) = (c^2)
look at the top triangle inside the big triangle. we know it's 2 sides but not the hypotenuse. one side would be 25 - 9 = 16 and other side is x. So so from theorem we know
16^2 + x^2 = h^2
with bottom triangle we can see the same thing but with 9 and x as the sides so:
9^2 + x ^2 = H^2 (capital H to distinguish them)
we also know that in the main triangle:
h^2 + H^2 = 25^2
now all we have to do is find a way to use these 3 equations to get the answer
we know what h^2 and H^2 both equal and can plug them into equation in orsee to get rid of one and solve for the other. So we use:
9^2 + x ^2 = H^2
and plug it into
h^2 + H^2 = 25^2
and get
h^2 + 9^2 + x ^2 = 25^2
solve for h^2
25^2 - x^2 - 9^2 = h^2
now plug what we got for h^2 into:
16^2 + x^2 = h^2
and get:
16^2 + x^2 = 25^2 - x^2 - 9^2
2x^2 = 25^2 - 16^2 - 9^2
2x^2 = 288
x^2 = 144
x = 12
there is your answer
Answer: (for 11b) 15/6
Step-by-step explanation:
I added image of how I solved (I’m 99% sure this is right)
Hope this helps :-))
Answer:
the reciprocal of one is 
it doesn't really make a difference it's still 1
Step-by-step explanation:
Answer:
y = (x-1/x+2)(x-1)
y = -3(x-1)
y = -3x+3
-3x y = 3
x y = -1
x(0) y = -1
y = -1
Step-by-step explanation:
