Answer:
12566.4 mm²
Step-by-step explanation:
The Petri dish shown has no lid. What is the surface area of the outside of the Petri dish? Round to the nearest tenth. A cylindrical-shaped Petri dish with a radius of 50 millimeters and a height of 15 millimeters.
TSA = Total Surface Area
CSA = Curved Surface Area
TSA of open cylinder = CSA of cylinder + area of base or top
= 2πrh + πr²
= πr(2h + r)
From the above question:
r = 50mm
h = 15mm
Hence,
= π × 50 (2 × 15 + 50)
= π × 50 (30 + 50)
= π × 50(80)
= π × 4000
= 12566.370614mm²
Approximately = 12566.4 mm²
The Surface Area of the petri dish with no lid = 12566.4 mm²
Answer:
~ fati235's answer ~
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Hope this helps!
It'll be -25... when u subtract -20 with 5 the answer will be -25
work:
(-20-5= -25)
Answer: The answer is: -2
Step-by-step explanation:
Here, suppose
(5,-2)=(x1, y1)
(-7,22)=(x2, y2)
Now, use the slope equation to find slope(m).
y2-y1=m(x2-x1)
or,m=y2-y1/x2-x1
After this, just substitute the values from above.
Z is 90 degrees.
Y is 31 degrees
X should be 31 degrees also
