3(x - 2) < 18 and h + 6 > -3h + 12 would be graphed with an open circle.
Open circle is a term used for numbers that are less than (<) or greater than (>). On the other hand, Closed circle is used for numbers that are less than or equal to (≤ ) and greater than or equal to (≥).
Here, we are given four inequalities, let us check them one by one-
A. h + 6 > -3h + 12
⇒ 4h > 6
or h > 3/2
Here, we see that there is no equality sign, this means that 3/2 won't be included and hence h + 6 > -3h + 12 would be an open circle inequality.
B. 7 ≥ d/3
⇒ d ≤ 21
Here, we can clearly see the equality sign which means that 21 will be included. Hence, 7 ≥ d/3 would not be graphed with an open circle.
C. 3(x - 2) < 18
x - 2 < 6
x < 8
Here, we see that there is no equality sign, this means that 8 won't be included and hence 3(x - 2) < 18 would be graphed with an open circle.
D. 2y ≤ 14
y ≤ 7
Here, we can clearly see the equality sign which means that 7 will be included. Hence, 2y ≤ 14 would not be graphed with an open circle.
Thus, 3(x - 2) < 18 and h + 6 > -3h + 12 would be graphed with an open circle.
Learn more about inequalities here-
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Answer:
9
Step-by-step explanation:
Just substitute the value of x onto the x variables in the equation
; 4(1)^2 + 5(1)
; 4 + 5
; 9
"Step 1: log 3^(x+1) = log15" is the step among the following choices given in the question that she did incorrectly. The correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer that has actually come to your desired help.
I think the answer is d hope this helps
