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gayaneshka [121]
3 years ago
5

Five point six times four point eight

Mathematics
1 answer:
LenaWriter [7]3 years ago
3 0

Answer:

26.88

Step-by-step explanation:start eight times four is 32

and than eight times six is 48 than add a zero and do four times six is 24

and four times five is twenty add it up and line up the decimal points

hope i helped !!

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Determine two pairs of polar coordinates for the point (5, 5) with 0° ≤ θ < 360°.
inna [77]

Answer:

First part

The answer is (5 square root 2, 45°), (-5 square root 2, 225°) ⇒ answer (d)

Second part

The equation in standard form for the hyperbola is y²/81 - x²/19 = 1 ⇒ answer(b)

Step-by-step explanation:

First part:

* Lets study the Polar form and the Cartesian form

- The important difference between Cartesian coordinates and

  polar coordinates:

# In Cartesian coordinates there is exactly one set of coordinates

  for any given point.

# In polar coordinates there is an infinite number of coordinates

   for a given point. For instance, the following four points are all

   coordinates for the same point.

# In the polar the coordinates the origin is called the pole, and

  the x axis is called the polar axis.

# The angle measurement θ can be expressed in radians

   or degrees.

- To convert from Cartesian Coordinates (x , y) to

  Polar Coordinates (r , θ)

# r = ± √(x² + y²)

# θ = tan^-1 (y / x)

* Lets solve the problem

- The point in the Cartesian coordinates is (5 , 5)

∵ x = 5 and y = 5

∴ r = ± √(5² + 5²) = ± √50 = ± 5√2

∴ tanФ = (5/5) = 1

∵ tanФ is positive

∴ Angle Ф could be in the first or third quadrant

∵ Ф = tan^-1 (1) = 45°

∴ Ф in the first quadrant is 45°

∴ Ф in the third quadrant is 180 + 45 = 225°

* The answer is (5√2 , 45°) , (-5√2 , 225°)

Second part:

* Lets study the standard form of the hyperbola equation

- The standard form of the equation of a hyperbola with  

  center (0 , 0) and transverse axis parallel to the y-axis is

  y²/a² - x²/b² = 1, where

• the length of the transverse axis is 2a

• the coordinates of the vertices are (0 , ±a)

• the length of the conjugate axis is 2b

• the coordinates of the co-vertices are (±b , 0)

•      the coordinates of the foci are (0 , ± c),  

• the distance between the foci is 2c, where c² = a² + b²

* Lets solve our problem

∵ The vertices are (0 , 9) and (0 , -9)

∴ a = ± 9 ⇒ a² = 81

∵ The foci at (0 , 10) , (0 , -10)

∴ c = ± 10

∵ c² = a² + b²

∴ (10)² = (9)² + b² ⇒ 100 = 81 + b² ⇒ subtract 81 from both sides

∴ b² = 19

∵ The equation is  y²/a² - x²/b² = 1

∴  y²/81 - x²/19 = 1

* The equation in standard form for the hyperbola is y²/81 - x²/19 = 1

3 0
3 years ago
calculate the scale factor of abc to def enter answer as a whole number or as a fraction into lowest terms
SVETLANKA909090 [29]

Answer:

Scale is 1/6

Step-by-step explanation:

Since all sides and angles are identical these are congruent triangles

3 ways to solve:

Scale Factor = DE / AB = 12/72 = 1/6

Scale Factor = DF/AC = 7/42 = 1/6

Scale Factor = EF/CB = 11/66 = 1/6

3 0
3 years ago
The concession stand is selling hot dogs and hamburgers during a game. At
MAVERICK [17]

Answer:

44 hotdogs

30 hamburgers

Step-by-step explanation:

b r a i n and p a p e r

7 0
3 years ago
Round 487.010 to the nearest whole number. Enter your answer in the space<br> provided
saw5 [17]

Answer:

487

Step-by-step explanation:

The answer is 487 because you must look one place to the right of the whole number for the rounding digit on the right side of the decimal point which is 0. Then you round down since the digit is not greater than 5.

.

5 0
3 years ago
How to Increase 8 by 9.4%
Fed [463]

Answer:

75.2

Step-by-step explanation:

multiple 8 by 9.4

4 0
3 years ago
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