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3 years ago

Meg uses 2 inches of ribbon to make each bow. how many bows can she make from 21 inches of ribbon?

Mathematics

1 answer:

Oduvanchick [21]3 years ago

3 0

21 divided by 2 is 10.5 so only 10 ribbons can be made

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A teacher needs 256 lengths of string cut to 40 cm each.if balls of string are 30 cm long how many balls will be needed

Elis [28]

256 * 40 = 10,240 cm needed

so if the balls are 30 cm each then

10, 240 divided by 30 = 341.3

so the teacher will need 342 balls.

7 0

2 years ago

The graph of a system of equations is

Dovator [93]

Answer:

The system has no solution.

Step-by-step explanation:

In order for the system to have a solution, both graphs must have an intercept to each others. We see in the picture that both graphs are parallel and do not have any interceptions which we don't know the solution to the system.

That means if graphs are parallel and have no interceptions, there are no solutions. The system of equations are for finding the interceptions of both graphs. But of course! Parallel lines do not intercept.

If you have any questions, feel free to ask.

6 0

3 years ago

What’s 690 divided by 4???

poizon [28]

172.5! hope this helps

6 0

2 years ago

Read 2 more answers

What is the first term of the geometric sequence whose fifth term is 1/24 and tenth term is 1/768

Neporo4naja [7]

An=a1r^(n-1)

given
a5=1/24
a10=1/768

we know that
a5=1/24=a1r^(5-1) and
a10=1/768=a1r^(10-1)

so
1/24=a1r^4
1/768=a1r^9

(a1r^9)/(a1r^4)=r^5=(1/768)/(1/24)=1/32

r^5=1/32
take 5th root of both sides
r=1/2

we have
a5=a1r^4=1/24
evaluate r^4 or (1/2)^4
1/16
a1(1/16)=1/24
times both sides by 16/1
a1=16/24
a1=2/3

the first term is 2/3

7 0

2 years ago

Mr eliot is extremely careful with his money. He recently invested part of his $150,000 life savings in gold bullion and the res

DIA [1.3K]

Answer:

The amount invested in gold bullion by Mr. Eliot = $50,000

Step-by-step explanation:

Total amount of savings Me. Eliot ha s = $150,000

Let us assume the amount invested in gold bullion = $m

So, the amount invested in bank = $150,000 - m

Now, 5% on m = $\frac{5}{100} \times m = 0.05 m$

So, the profit in gold bullion = 0.05 m

and 3% on (150,000 -m) = $\frac{3}{100} \times (150,000 -m) = 0.03 (150,000 -m)$

= 4,500 - 0.03 m

So, the profit in bank = 4,500 - 0.03 m

Now, the total profit = $5,500

⇒Profit from gold bullion + ban = $5,500

⇒0.05 m + 4,500 - 0.03 m = $5,500

or, 0.02 m = 1000

⇒ m = 1000/0.02 = 50,000

Hence, the amount invested in gold bullion = m = $50,000

3 0

3 years ago