Write each fraction or mixed number as a decimal. 27/75

If there is 1000$ in the lockbox what year will it be worth 64,000$ at 24% interest?

Leni [432]

Hey there!

First, set up an exponential equation that represents the rate at which your original amount, 1000, gains interest:

y = 1000(1.24)^x

Y represents the value after X years. 1.24 represents the rate at which the money gains interest, 1 + 0.24 (your 24% interest rate in decimal form). 1000 is your original amount.

Now, set this equation equal to 64000, graph y = 64000 and y = 1000(1.24)^x on a graphing calculator, and see where the two equations intersect in order to solve for x.

They intersect when x is about 19.334, as seen in the graph below (it is very zoomed in so that you can see where the two functions intersect). Therefore, it will be about 19 years after the year in which you deposited the 1000 dollars before the money is worth 64000 dollars.

7 0

3 years ago

Is it a function or non function?

Otrada [13]

It is a function because each x values have ONE y value

6 0

4 years ago

What is the value of x?<br><br>I know the answer is 2 but i need a explanation as to how to get that

likoan [24]

When 2 secants intersect a circle:
(DC + CE) * CE = (AB + BE) * BE

( 1 + (x+4)) * (x+4) = (11 + (x+1)) * (x+1)

x + x^2 + 4x + 4 +4x +16 = 11x +x^2 +x +11 +x +1

9x + 20 = 13x + 12

4x = 8

x = 2

Source:
http://www.1728.org/circangl.htm
Scroll down to Two Intersecting Secants

Gee - that was a little bit of work!!

5 0

3 years ago

A contractor is building a new subdivision on the outside of a city. He has started work on the first street and is planning for

ruslelena [56]

You can use those two given points of street 1 to form its equation, then can use the fact that parallel lines have same slope to find the equation of second street with the help of the point (1,5) which lies in second street.

The equation of the location of the second street in standard form is given as $2y = x + 9$

<h3>What is the equation of a straight line passing through two given points?</h3>

Let the two given points be (a,b) and (c,d). Then the equation of straight line passing through these two points is given by:

$y - b = \dfrac{(d-b)}{(c-a)}(x-a)$

<h3>What is slope intercept form of equation of straight line?</h3>

y = mx + c is the slope intercept form of straight line where m is the slope and c is the y-intercept (where the straight line cut on y = c at y axis) of the given line.

<h3>How to find equation of second street's location in terms of equation of straight line?</h3>

Firstly we will find the equation of straight line which represents street 1.

Since street 1 goes from point (-5,-6) and (3,-2), thus, its equation would be:

$y - (-6) = \dfrac{-2- (-6)}{3-(-5)} (x -(-5))\\
\\
y + 6 = \dfrac{1}{2}(x+5)\\
\\
y + 6 = \dfrac{x}{2} + \dfrac{5}{2}\\\\
y = \dfrac{x}{2} -\dfrac{7}{2}$

Thus, this above equation represents equation of location of street 1. The slope is 1/2 and y-intercept is -7/2.

Since the street 2 is parallel to street 1, thus we have its slope same as that of street 1. Writing the equation in slope intercept form we get:

$y = \dfrac{1}{2}x + c$

Since street 2 passes through (1,5)( x= 1, y = 5), thus, this point must satisfy above equation which represents all points lying on street 2.

Thus,

$5 = \dfrac{1}{2} \times 1 + c\\\\
c = 5 - \dfrac{1}{2} = \dfrac{9}{2}$