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3 years ago

Find the area of a circle with a radius of 6.7 m to the nearest square unit

Mathematics

2 answers:

dem82 [27]3 years ago

8 0

Answer:

141 Square units.

Step-by-step explanation:

Area of a circle is equal to pi*radius squared.

$A = \pi \times 6.7^{2} \\A = 141.026....\\A \approx 141 u^2$

Dennis_Churaev [7]3 years ago

7 0

Answer:

A = 141 m²

Step-by-step explanation:

The formula of an area of a circle with radius r:

$A_O=\pi r^2$

We have r = 6.7m. Substitute:

$A_O=\pi\cdot6.7^2=\pi\cdot44.89\approx3.14\cdot44.89=140.9546\approx141\ m^2$

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The are of a rectangle is 525 square centimeters. The ratio of the length to the width is 7: 3. Find the length and the width.

prohojiy [21]

I hope this helps you

width 3x

length 7x

3x.7x =525

21.x^2 =21.25

x^2=5^2

x=5

length 7x=7.5 =35

width 3x=3.5=15

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2 years ago

10−8(−7y−4) find the sum

Sindrei [870]

Answer:

56y+32

Step-by-step explanation:

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5 0

3 years ago

Can u please help me with these two questions .

scoundrel [369]

Question 1
2x + 4 + x - 7 = 3(x-7)
Add like terms, x-terms add
3x + 4 - 7 = 3(x-7)
Subtract 7 from 4
3x - 3 = 3(x-7)
Multiply out right side with distributive property, 3 times x, and 3 times -7
3x -3 = 3x - 21
Add 21 on each side to cancel -21 on right
3x + 18 = 3x
This is impossible, 3x + 18 cannot equal 3x, plug value in to check, 3(1) + 18 = 3(1), 21 not equal to 3
Question 1 Answer : No Answer

Question 2
4(m-2) = -3(m-16)
Multiply using distributive property on each side
4m - 8 = -3m + 48
Add 8 on each side to cancel -8 on left
4m = -3m + 56
Add 3m on each side to cancel -3m on right
7m = 56
Divide 7 on each side to make 7m : m
m = 56/7
m = 8
Answer to Question 2 : 8

3 0

3 years ago

Use cylindrical coordinates. find the volume of the solid that is enclosed by the cone z = x2 + y2 and the sphere x2 + y2 + z2 =

sashaice [31]

Let $R$ be the solid. Then the volume is

$\displaystyle\iiint_R\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=\sqrt8}\int_{\zeta=r^2}^{\zeta=\sqrt{72-r^2}}r\,\mathrm d\zeta\,\mathrm dr\,\mathrm d\theta$

which follows from the facts that

$\begin{cases}x=r\cos\theta\\y=r\sin\theta\\z=\zeta\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=r\,\mathrm dr\,\mathrm d\theta\,\mathrm d\zeta$
(by computing the Jacobian)

and

$z=x^2+y^2=r^2\implies z+z^2=72\implies z=-9\text{ or }z=8$
(we take the positive solution, since it's clear that $R$ lies above the $x$ - $y$ plane)
$r^2+z^2=72\implies z=\pm\sqrt{72-r^2}$
(again, taking the positive root for the same reason)
$z=r^2\implies 8=r^2\implies r=\sqrt8$

$\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=\sqrt8}\int_{\zeta=r^2}^{\zeta=\sqrt{72-r^2}}r\,\mathrm d\zeta\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=\sqrt8}\int_{\zeta=r^2}^{\zeta=\sqrt{72-r^2}}r\,\mathrm d\zeta\,\mathrm dr$
$=\displaystyle2\pi\int_{r=0}^{r=\sqrt8}r(\sqrt{72-r^2}-r^2)\,\mathrm dr$
$=\displaystyle2\pi\int_{r=0}^{r=\sqrt8}(r\sqrt{72-r^2}-r^3)\,\mathrm dr$
$=\dfrac{32(27\sqrt2-35)\pi}3$

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3 years ago

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bonufazy [111]

Step-by-step explanation:

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3 years ago

Read 2 more answers