Question

Solve the following system by the substitution method. Check the solution.

Answer 1

$\left \{ {{3x + 6y = 4x} \atop {x = 8- 2y}} \right.$

$\left \{ {{3x- 4x + 6y = 0} \atop {x = 8 - 2y}} \right.$

$\left \{ {{-x + 6y = 0} \atop {x=8 - 2y}} \right.$

$\left \{ {{-(8-2y) + 6y} \atop {x=8 - 2y}} \right.$

$\left \{ {{-8+2y +6y = 0} \atop {x=8 - 2y}} \right.$

8y = 8
y = 1

x = 8-2y
x = 8-2*1
x = 8-2
x = 6



A.
The system has a single solution. The solution set is (6, 1)